In this problem it is asking how many gallons the pool holds. It gives you a method of exchange from cubic feet to this however, so in order to solve for this, we first have to solve for how many cubic feet is in the swimming pool, or how much volume the swimming pool has. The formula for the volume of a rectangle is Length*Width*Depth=Volume. Plugging in what we have we get 30*20*6=Volume, or Volume = 3600. As there are 7.5 gallons of water in each cubic foot, we simply multiply 7.5 times 3600 to get the answer. This is 27000.
Answer:
option A
12m/s
Step-by-step explanation:
Given in the question,
mass of object = 11kg
kinetic energy possess by = 792 joules
To find the velocity we use formula
v = 
Plug values in the formula
v = 
v = 
v = 
v= 12 m/s
Answer:
Average rate of change is <u>0.80.</u>
Step-by-step explanation:
Given:
The two points given are (5, 6) and (15, 14).
Average rate of change is the ratio of the overall change in 'y' and overall change in 'x'. If the overall change in 'y' is positive with 'x', then average rate of change is also positive and vice-versa.
The average rate of change for two points 
is given as:
Plug in 
and solve for 'R'. This gives,
Therefore, the average rate of change for the points (5, 6) and (15, 14) is 0.80.
The equation of the circle is written as: (x - h)² + (y - k)² = r²
(h,k) are the points of the center of the circle.
r is the radius.
In case of the given equation the center is (-3,-5)
Hope this helps :)
<span>ow far does the first car go in the 2 hours head start it gets?
Now, at t = 2 hours, both cars are moving. How much faster is the second car than the first car? How long will it take to recover the head start? You can determine this by dividing the head start by the difference in the two speeds. If car 1 has a 20 mile head start, and car 2 is 5 mph faster, then it will take 20/5 = 4 hours to catch up.
</span>You could also write two equations, one for each car, showing how far they have gone in a variable amount of time. Set the two equations equal to each other and solve for the value of the time. Note that the second car's equation will use (t-2) for the time, because it doesn't start driving until t = 2.
