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Trava [24]
3 years ago
14

Find the distance between the pair of points. E(7-2), F(-2,10) d=

Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0
The answer is 15.
Using the distance formula you’d get. Sqrt(-2-7)^2+(-10-2)^2

Sqrt(-9)^2+(-12)^2

Sqrt(81+144)

Sqrt(225)

D=15
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Y=23x y=-x+5y=−x+5 pls help
irina1246 [14]
Sorry only doing this for points
5 0
2 years ago
If f(n)=(n-1)2+<br><img src="https://tex.z-dn.net/?f=f%28n%29%20%3D%20%28n%20-1%292%20%2B%20%20%20%203n" id="TexFormula1" title=
Liono4ka [1.6K]

Distribute the 2 first.

f(n) = 2n - 2 + 3n

Combine like terms.

f(n) = 5n - 2

8 0
3 years ago
Solve the Equation<br> -8.3 = d+4.7
alukav5142 [94]

Answer:

d = -13

Step-by-step explanation:

-8.3 = d + 4.7

-8.3 - 4.7 = d

-13 = d

6 0
2 years ago
Read 2 more answers
Six over ten &gt;_______&gt; one over two
Vinvika [58]
Six over ten over one over two is 0.3
5 0
3 years ago
A rental car company charges $150.00 for a weekly rental and an additional $0.20 for each mile driven. The function rule C = 0.2
son4ous [18]

Answer:

A rental car company charges $150.00 for a weekly rental and an additional $0.20 for each mile driven.

The function  C = 0.20m+ 150.00 ,

where m is the number of miles and C is the total cost.

Since it is given that : If the rental car can only be driven a maximum of 200 miles.

Then the total cost for this is,

C = 0.20 (200)+150 or

C= 40+150

On simplify we get,

C = \$ 190

A rental Car can only be driven a maximum of 200 miles for a cost of $ 190.

Graph the function : C = 0.20m+ 150.00 as shown in the attachment.  




7 0
3 years ago
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