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3 years ago

A can of soda is placed inside a cooler. As the soda cools, its temperature T(x)

Mathematics

1 answer:

solniwko [45]3 years ago

8 0

Answer:

The initial temperature of the soda is 16°C

The temperature of the soda after 18 minutes is -12°C

Step-by-step explanation:

T(x) = -12+28e^-0.38x

When x = 0

T(0) = -12+28e^-0.38(0) = -12+28e^0 = -12+28(1) = -12+28 = 16°C

Initial temperature of the soda is 16°C

When x = 18

T(18) = -12+28e^-0.38(18) = -12+28e^-6.84 = -12+28(0.0011) = -12+0.0308 = -11.9692°C = -12°C (to the nearest degree)

The temperature of the soda after 18 minutes is -12°C

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Answer:

Step-by-step explanation:

Replace your variables with the numbers given.

0.1m + 8 - 12n =

0.1 · 30 + 8 - 12 · 1/4 =

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3 years ago

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MakcuM [25]

Answer:

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Step-by-step explanation:

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2 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

3 years ago

Mrs. Figueroa made a spaghetti dinner for the cheerleaders after practice. She purchased 42 pounds of beef for $3.99 per pound.

Zigmanuir [339]

The answer is $167.58 you check it be multiplying 3.99x42

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1 year ago

Read 2 more answers

Natara is training to run a 26-mile marathon. Each week, she increases the distance she runs on her training days. Over the firs

ValentinkaMS [17]

Answer:

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Step-by-step explanation:

For each week add 3 miles until you reach 26 miles

Week 1:5

Week 2:5+3=8

Week 3:8+3=11

Week 4:11+3=14

Week 5:14+3=17

Week 6:17+3=20

Week 7:20+3=23

Week 8:23+3=26

Hope this answers your question :)

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2 years ago