Question

A can of soda is placed inside a cooler. As the soda cools, its temperature T(x)

Answer 1

Answer:

The initial temperature of the soda is 16°C

The temperature of the soda after 18 minutes is -12°C

Step-by-step explanation:

T(x) = -12+28e^-0.38x

When x = 0

T(0) = -12+28e^-0.38(0) = -12+28e^0 = -12+28(1) = -12+28 = 16°C

Initial temperature of the soda is 16°C

When x = 18

T(18) = -12+28e^-0.38(18) = -12+28e^-6.84 = -12+28(0.0011) = -12+0.0308 = -11.9692°C = -12°C (to the nearest degree)

The temperature of the soda after 18 minutes is -12°C