The exponent indicates how many times the base is used as a factor.
Answer: 0.395 km
Step-by-step explanation:
Let Martin distance from the hole be X
On first stroke, his golf ball traveled 4/5 of the distance to the hole. That is 4/5 X
On his second stroke, the ball traveled 79 meters and went into the hole
Total distance covered will be
X = 79 + 4/5X
X - 4/5X = 79
X - 0.8X = 79
0.2X = 79
X = 79/0.2 = 395 meters
How many kilometers from the hole was Martin when he started
X = 395/1000 = 0.395 km
Answer:
NOT true:
A, C, D
Step-by-step explanation:
For this case we have the following fractions:

We must rewrite the fractions, using the same denominator.
We have then:
We multiply the first fraction by 11 in the numerator and denominator:

We multiply the second fraction by 2 in the numerator and denominator:

Rewriting we have:
For the first fraction:

For the second fraction:

We note that:

Answer:
The fractions are not equivalent:

Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60