-6(-3)=18, so that is true
-6+(-3)=-6-3=-9 so that is true
-6-(-3)=-6+3=-3 FALSE
-6 ÷ (-2)=2 so that is true
Answer is C
Answer:
x = 1, y = 2
Step-by-step explanation:
In the elimination method to solve a system of linear equations, one of the two equations is added/subtracted to the other, in order to eliminate one variable from the equation.
In this problem, we have the following two equations:
To solve the system, first we multiply by 2 both sides of the second equation, and we get:
So now the system is
Now we add the two equations, and we get:
So, we get
Now we can substitute this value of y into the eq.(2), and we get:
Answer:
q=35
Step-by-step explanation:
x2 - 12x + q = 0
Let the two roots be r and r+2.
Factor the quadratic expression:
(x - r)[x - (r + 2)] = 0
Expand, simplify, group like terms, and get
x2 - 2(r + 1)x + r(r + 2) = 0
Compare to
x2 - 12x + q = 0
and set equal the coefficients of like terms:
Coefficient of x:
-2(r + 1) = -12 ⇒ r + 1 = 6 ⇒ r = 5
(Then the other root is r + 2 = 5 + 2 = 7)
Constant term:
r(r + 2) = q ⇒ 5(5 + 2) = q
q = 35
Test the solution:
(x - 5)(x - 7) = x2 - 12x + 35
With two roots differing by 2, you get an equation of the form
x2 - 12x + q = 0
with q = 35.
Answer:
(8*2)-2
Step-by-step explanation:
17 + 3y = 7x
3y = 7x - 17
y = 7/3x - 17/3
= 7/3
