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krek1111 [17]
3 years ago
15

How to simplify this

Mathematics
1 answer:
Slav-nsk [51]3 years ago
7 0
Factor it out.
Both exponent cancel out each other which equals 1.
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Meg mixes 3 parts silver paint with 4 parts green paint to get a specific color. Is the ratio 5:6 equivalent to 3:4?
damaskus [11]

Answer:

No, because the numbers in the given ratio must be multiplied by the same number.

Step-by-step explanation:

Essentially, ratio to be equal must be equal. E.g. 3:4 would be equal to 6:8 because you multiply both sides of the ratio by 2.

7 0
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What name best describes this polygon? trapezoid rectangle quadrilateral rhombus
8_murik_8 [283]
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The denominator of a fraction is 9 more than the numerator. if both the numerator and the denominator are decreased by 1 the res
yarga [219]
X/x+9 (original fraction)

x+1/ x+10 = 4/13

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now that you have the value of x, substitute it into the original fraction to get:

3/12
5 0
3 years ago
Use Cramer Rule to solve the following system: 8x−5y=70 and 9x+7y=3
nlexa [21]

Answer:

(x,y) = (5,-6)

Step-by-step explanation:

\underline{\textbf{Determinant of a matrix.}}\\\\\text{For a}~ 2 \times 2 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2\\b_1&b_2 \end{vmatrix} = a_1b_2 - a_2b_1\\\\\\\text{For a}~ 3 \times 3 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2&a_3\\ b_1&b_2&b_3\\ c_1&c_2&c_3 \end{vmatrix} = a_1\begin{vmatrix} b_2&b_3\\c_2&c_3 \end{vmatrix} - a_2 \begin{vmatrix} b_1&b_3\\c_1&c_3 \end{vmatrix}+ a_3 \begin{vmatrix} b_1&b_2\\c_1&c_2 \end{vmatrix}\\\\\\

                     ~~~~~~~~~~~~~~~~~~=a_1(b_2c_3-b_3c_2) -a_2(b_1c_3-b_3c_1) +a_3(b_1c_2-b_2c_1)

\underline{\textbf{Cramer's Rule to solve a system of two equations.}}\\\\\text{Consider the system of two equations:}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_1x + b_1 y= c_1\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_2x +b_2 y = c_2\\\\\text{Here,}\\\\x = \dfrac{D_x}{D}= \dfrac{\begin{vmatrix} c_1&b_1\\c_2&b_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\\\ y= \dfrac{D_y}{D}= \dfrac{\begin{vmatrix} a_1&c_1\\a_2&c_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\

\underline{\textbf{Solution:}}\\\\~~~~~~~~~~~~~~~~~~~~~~~8x-5y = 70~~~~~~...(i)\\\\~~~~~~~~~~~~~~~~~~~~~~~9x +7y = 3~~~~~~~...(ii)\\\\\text{Applying Cramer's rule:}\\\\x = \dfrac{D_x}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 70& -5 \\3&7 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{70(7) -(-5)(3)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{490+15}{56+45}\\\\\\~~=\dfrac{505}{101}\\\\\\~~=5

y = \dfrac{D_y}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 8& 70 \\9&3 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{(8)(3) -(70)(9)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{24-630}{56+45}\\\\\\~~=-\dfrac{606}{101}\\\\\\~~=-6

\textbf{Hence, the solution to the system of equation is}~ (x,y) = (5,-6)

7 0
1 year ago
Person A can make a cupcake in 5 minutes, Person B can make a cupcake in 9 minutes. In total they made 168 cupcakes. How many cu
Stolb23 [73]

Answer:

Person A made 108 cupcakes and person B made 60 cupcakes.

Step-by-step explanation:

Person A makes 1 cupcake in 5 minutes.

Say in x minutes A makes : \frac{x}{5} cupcakes

Person B makes 1 cupcake in 9 minutes.

Say in x minutes B makes : \frac{x}{9} cupcakes

Total cupcakes prepared by A and B in x minutes = 168

\frac{x}{5}+\frac{x}{9}=168

\frac{14x}{45}=168

x=\frac{168\times 45}{14}=540

So, cupcakes made by A = \frac{540}{5}=108

Cupcakes made by B = \frac{540}{9}=60

Person A made 108 cupcakes and person B made 60 cupcakes.

5 0
3 years ago
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