Answer:
a) The model for the sales of Garmin is represented by 
.
b) The average sales of Garmin from 2008 through 2013 were $ 2.5 billion.
Step-by-step explanation:
a) The model for the sales of Garmin is obtained by integration:
(1)
Where 
is the integration constant.
If we know that 
and 
, then the model for the sales of Garmin is:
The model for the sales of Garmin is represented by .
b) The average sales of the Garmin from 2008 through 2013 (
) is determined by the integral form of the definition of average, this is:
(2)
![\bar S = \frac{1}{5}\cdot \int\limits^{13}_{8} {\left[-\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2}-11.9\cdot t + 47.112 \right]} \, dt](https://tex.z-dn.net/?f=%5Cbar%20S%20%3D%20%5Cfrac%7B1%7D%7B5%7D%5Ccdot%20%5Cint%5Climits%5E%7B13%7D_%7B8%7D%20%7B%5Cleft%5B-%5Cfrac%7B81%7D%7B2500%7D%5Ccdot%20t%5E%7B3%7D%20%2B%20%5Cfrac%7B267%7D%7B250%7D%5Ccdot%20t%5E%7B2%7D-11.9%5Ccdot%20t%20%2B%2047.112%20%20%5Cright%5D%7D%20%5C%2C%20dt)
![\bar S = \frac{1}{5}\cdot \left[-\frac{81}{10000}\cdot (13^{4}-8^{4}) +\frac{89}{250}\cdot (13^{3}-8^{3}) -\frac{119}{20}\cdot (13^{2}-8^{2}) +47.112\cdot (13-8) \right]](https://tex.z-dn.net/?f=%5Cbar%20S%20%3D%20%5Cfrac%7B1%7D%7B5%7D%5Ccdot%20%5Cleft%5B-%5Cfrac%7B81%7D%7B10000%7D%5Ccdot%20%2813%5E%7B4%7D-8%5E%7B4%7D%29%20%2B%5Cfrac%7B89%7D%7B250%7D%5Ccdot%20%2813%5E%7B3%7D-8%5E%7B3%7D%29%20-%5Cfrac%7B119%7D%7B20%7D%5Ccdot%20%2813%5E%7B2%7D-8%5E%7B2%7D%29%20%2B47.112%5Ccdot%20%2813-8%29%20%20%20%5Cright%5D)
The average sales of Garmin from 2008 through 2013 were $ 2.5 billion.
Answer:
8
Step-by-step explanation:
4+4=8
50 Is the answer.........
Answer:
no
Step-by-step explanation:
The second purchase is exactly half-again larger than the first purchase, so sheds no light on the relative costs of the items. The per-item costs can be found when the ratio of items purchased is different from one buy to another.
___
We can only say that the cost of 1 pear and 3 apples is $7.
Answer:
The solution of system of equation is (-2,0)
Step-by-step explanation:
Given system of equation are
Equation 1 : 2x+y=(-4)
Equation 2 : y+
x=(-1)
To plot the equation of line, we need at least two points
For Equation 1 : 2x+y=(-4)
Let x=0
2x+y=(-4)
2(0)+y=(-4)
y=(-4)
Let x=1
2x+y=(-4)
2(1)+y=(-4)
y=(-6)
Therefore,
The required points for equation is (0,-4) and (1,-6)
For Equation 2 : y+x=(-1)
Let x=0
y+x=(-1)
y+(0)=(-1)
y=(-1)
Let x=2
y+x=(-1)
y+(2)=(-1)
y=(-2)
The required points for equation is (0,-1) and (2,-2)
Now, plot the graph using this points
From the graph,
The red line is equation 1 and blue line is equation 2
Since. The point of intersection is solution of system of equations
The solution of system of equation is (-2,0)
