Given:
The graph of a function 
.
To find:
The interval where 
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, for 
and 
.
The function between x=0 and x=3.6 lies below the x-axis. So, 
for 
.
Now,
For 
, the graph of h(x) is above the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
Only for the interval , we get .
Therefore, the correct option is A.
It would be $1.50 because if the soda's $1 then subtract it and divide that by the quantity.
The geometric sequence is a sequence in which the proceeding number is equal to the preceeding number multiplied by a ratio. The expression that represents this sequence is an = a1*r^(n-1) where r is the ratio and n is an integer. This type of formula is exponential
Basically they're both equal
4x-3=x+7
-x. -x
3x-3=7
+3 +3
3x=10
X=10/3
Hope you have got the answer to this question. If not, here it is:
(a² -b²) +(a+b)
(a+b)(a-b)+(a+b)
(a+b)(a-b+1)
