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o-na [289]
3 years ago
11

I need help with this one

Mathematics
1 answer:
olga55 [171]3 years ago
8 0

Answer:

(5,5)

Step-by-step explanation:

you subtract 1 from 6 and 2 from seven like they did in (7,9) to (6,7)

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Which of the following statements are true about the equation below?
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Read 2 more answers
Help? im confused plss!<br> Find the area of the regular polygon with the given radius or apothem
Snezhnost [94]

Answer:

  50 cm²

Step-by-step explanation:

Given that the regular polygon is a square, there are multiple ways you can jump directly to the answer. Perhaps the simplest is to use the formula for the area of a rhombus:

  A = 1/2(d1)(d2)

where d1 and d2 are the lengths of the diagonals. Here, we see that half the diagonal is 5 cm, so the area is ...

  A = (1/2)(10 cm)(10 cm) = 50 cm² . . . . area of the polygon

__

<em>Alternate solution</em>

If you want to use the radius and the number of sides in a formula, you can consider the area of each triangle formed by radii and a side. That triangle has area ...

  A = 1/2r²sin(α)

where r is the radius and α is the central angle. For an n-sided polygon, the area is the sum of n of these triangles, and the central angle is 360°/n. Then the polygon area is ...

  A = n/2·r²·sin(360°/n)

For n = 4 and r = 5 cm, the area is ...

  A = (4/2)(5 cm)²(sin(360°/4)) = 2(5 cm)²(1) = 50 cm² . . . . area of square

_____

<em>Additional comment</em>

The formula is somewhat different if you start with the length of the apothem. One way to find the area is using the above formula and the relation between the radius and apothem:

  r = a·sec(180°/n)

Another formula uses the apothem directly:

  A = n·a²·tan(180°/n)

8 0
2 years ago
Will someone please tell me step by step how to solve this.
Gwar [14]
I believe you set them equal to each other.
2x+4=5x-9
x=4.3
2(4.3)+4=12.6
I think the answer is 12.6
6 0
3 years ago
Which is the solution to the equation: 1/3 (9x+2)=4+2/3 (6x+4)
Ne4ueva [31]

Answer:

The answer is x= -6 !

Step-by-step explanation:

4 0
3 years ago
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