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o-na [289]
3 years ago
11

I need help with this one

Mathematics
1 answer:
olga55 [171]3 years ago
8 0

Answer:

(5,5)

Step-by-step explanation:

you subtract 1 from 6 and 2 from seven like they did in (7,9) to (6,7)

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Which of the following inequalities is equivalent to 3-(w+2)>4+2w
Kay [80]

3 - w - 2 > 4 + 2w  \\  - w - 2w > 4 + 2 - 3 \\  - 3w > 6 - 3 \\   \frac{ - 3w}{ - 3}  >  \frac{3}{ - 3} \\ w <  - 1
The sign at the end changes because both sides of the equation are being divided by a negative number.
4 0
2 years ago
Read 2 more answers
Parallelogram ABCD is shown.<br>​
hichkok12 [17]

Answer:

Step-by-step explanation:

#4 part A= D

#4 part B = 76

Your question only states parrallelogram ABCD is shown, so I assume you only wanted those answers, GL

3 0
1 year ago
What is the sum of the measures of the interior angles of a 14-gon?
ICE Princess25 [194]
D 2520 -------------------------------------------
6 0
3 years ago
The midpoint of RS is M(1, 2). One endpoint is R(-6, 6). Find the coordinates of endpoint S.
AysviL [449]

Answer:

The coordinates of point S are (8,-2)

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

M=(\frac{x1+x2}{2},\frac{y1+y2}{2})

Let

Point S(x2,y2)

substitute the given values

(1,2)=(\frac{-6+x2}{2},\frac{6+y2}{2})

<em>Solve for x2</em>

1=(-6+x2)/2\\2=-6+x2\\x2=2+6=8

<em>Solve for y2</em>

2=(6+y2)/2\\4=6+y2\\y2=4-6=-2

therefore

The coordinates of point S are (8,-2)

5 0
3 years ago
Tell whether each of the following is a function.
n200080 [17]
Options A, C and D are functions.

In a function, for every number for 'x' there is only one 'y'. So, if you have two ordered pairs in a choice that have the same number for 'x', that is not a function.

Remember an ordered pair is written (x, y).

B is not a function as:
(x, y)
(1, -2)
(1, -3)
(1, -4)
^ All of the x-coordinates are the same.

E is not a function as:
(x, y)
(6, -1)
(6, -8)
^ Two of the x-coordinates are the same.

Thus, A, C and D are functions.
6 0
2 years ago
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