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3 years ago

What is the answer? Need help asap! The answer isn’t 13.9 btw. 20 points!

Mathematics

2 answers:

KIM [24]3 years ago

7 0

Answer:

y = 12

Step-by-step explanation:

Looking at the large triangle

tan 30 = opposite / adjacent

tan 30 = 4 sqrt(3)/ y

Multiply each side by y

y tan 30 = 4 sqrt (3)

We know tan 30 = sqrt(3)/3

y * sqrt(3)/3 = 4 sqrt(3)

Multiply each side by 3/ sqrt(3) to isolate y

y * sqrt(3)/3 * 3/ sqrt(3) = 4 sqrt(3) * 3 /sqrt(3)

y = 12

inessss [21]3 years ago

4 0

Answer:

y = 12

Step-by-step explanation:

tan(theta) = opposite/adjacent

tan(60) = y/4sqrt(3)

y = 4sqrt(3) × tan(60)

y = 12

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How may shells does Joshua have?

Tpy6a [65]

24, since 54-30 is 24, and 30+24 is 54.

5 0

3 years ago

Read 2 more answers

List 3 values that would make this inequality true 43 < y -30

prohojiy [21]

43 < y - 30
add 30 to both sides
73 < y

y can be anything that is greater than 73
so it could be...
101, 74, 90, 75, 980767, 5674, etc.

Hope this helps!

4 0

3 years ago

Identify the area of a regular decagon with side length 2 m rounded to the nearest tenth

Zina [86]

Answer:

Area = 14.8

Step-by-step explanation:

Area = 5/2 + a^2*sqrt(5 + 2 sqrt(5) )

This formula given the side length, calculates the area.

a = 2

Area = 2.5 + 2^2 * sqrt(5 + 2*sqrt(5) )

Area = 2.5 + 4 * sqrt(5 + 2*2.236)

Area = 2.5 + 4* sqrt(5+ 4.4721)

Area = 2.5 + 4*sqrt(9.4721)

Area = 2.5 + 4*3.0776

Area = 2.5 + 12.3107

Area = 14.8107

5 0

3 years ago

In a bag there are 4 purple marbles, 3 green marbles, and 10 yellow marbles. If a student draws one marble what is the sample sp

guajiro [1.7K]

The correct answer Is D. Purple , Green , Yellow

Hope I helped! ( Smiles )

6 0

3 years ago

I need help with number 4

Nadusha1986 [10]

$\bf \begin{cases}
\quad3x+2y=-9\\
-10x+5y=-5
\end{cases}$

so hmm the idea behind the elimination, is to make the value atop or below, of either variable, the same but with a negative sign

so hmmm say... we'll eliminate "y"

so... let's see, we have 2y and 5y, both positive
what do we multiply 2y to get a negative -5y, that way, -5y +5y = 0 and poof it goes

well let's see, let's try "k" $\bf 2yk=-5y\implies k=-\cfrac{5y}{2y}\implies k=-\cfrac{5}{2}$

so.. if we multiply 2y by -5/2, we'll end up with -5y

well, let's multiply that first equation then by -5/2

$\bf \begin{array}{rllll}
3x+2y=-9&\qquad\times -\frac{5}{2}\implies &-\frac{15}{2}x-5y=\frac{45}{2}\\\\
-10x+5y=-5&\implies &-10x+5y=-5\\
&&---------\\
&&\frac{-35}{2}x+0\quad=\frac{35}{2}
\end{array}\\\\
-----------------------------\\\\
\cfrac{-35}{2}x=\cfrac{-35}{2}\implies \cfrac{-35x}{2}=\cfrac{-35}{2}\implies x=\cfrac{2}{-35}\cdot \cfrac{-35}{2}
\\\\\\
\boxed{x=1}$

so.. now we know x = 1.... so let's plug that in say hmmm 2nd equation

$\bf -10(1)+5y=-5\implies -10+5y=-5\implies 5y=5\implies\boxed{ y=1}$

3 0

3 years ago