Answer:
a) 81.5%
b) 95%
c) 75%
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 266 days
Standard Deviation, σ = 15 days
We are given that the distribution of length of human pregnancies is a bell shaped distribution that is a normal distribution.
Formula:
a) P(between 236 and 281 days)
b) a) P(last between 236 and 296)
c) If the data is not normally distributed.
Then, according to Chebyshev's theorem, at least data lies within k standard deviation of mean.
For k = 2
Atleast 75% of data lies within two standard deviation for a non normal data.
Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.
B= 20°
and c = 160°
b is equal to the given angle, b = 20°
c is 180 - 20 = 160°
Solutions
Gather like terms
<span /><span><span><span><span><span><span>5</span><span>+</span><span>(</span><span>−</span><span>9</span><span>k</span><span>+</span><span>8</span><span>k</span><span>)</span><span>−</span><span>8</span></span><span /></span></span><span /></span></span>2<span>
</span>
Simplify
<span /><span><span><span><span><span><span>5</span><span>−</span><span>k</span><span>−</span><span>8
</span></span><span /></span></span><span /></span></span>
<span> </span>Simplify
<span /><span><span><span><span><span><span>−</span><span>k</span><span>−</span><span>3</span></span><span /></span></span><span /></span><span>
</span></span>
Answer:
8
Step-by-step explanation: