Step-by-step explanation:
W=-6, x=1.2, and z=-6/7
(W²x-3)÷10-z
we substitute
((-6²)(1.2)-3)÷10-(-6/7)
((-36)(1.2)-3) ÷10-(-6/7)
(-43.2-3) ÷10(6/7)
(-46.2)÷60/7
-46.2÷60/7
-46.2*7/60
-46.2/1*7/60
-323.4/60
-5.39
The quotient is 5x+3 and the remainder is 5/x-1
my work is attached below
No "x" can not be repeated, a function has one x-element and one y-element
You're looking for a value

such that

Because the distribution is symmetric, the value of

in either case will be the same.
Now, because the distribution is continuous, you have that

The mean for the standard normal distribution is

, and because the distribution is symmetric about its mean, it follows that

.

You can consult a

score table to find the corresponding score for this probability. It turns out to be

.