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pashok25 [27]
3 years ago
15

Question

Mathematics
1 answer:
Semenov [28]3 years ago
6 0

Answer: B

Step-by-step explanation:

We are given that a 45-45-90 triangle has a hypotenuse of 7\sqrt{2}.

In a 45-45-90 triangle, the legs are congruent. Therefore we can use the Pythagorean Theorem to solve.

a^2+a^2=(7\sqrt{2})^{2}         [combine like terms]

2a^2=(7\sqrt{2})^2               [square root both sides]

a\sqrt{2} =7\sqrt{2}                 [divide both sides by root 2]

a=7

Now, we know that a leg is length 7, which is B.                

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Answer:

56

Step-by-step explanation:

A negative times a negative makes a positive, so:

-7*(-8)=56

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The percent frequency distributions of job satisfaction scores for a sample of information systems (IS) senior executives and mi
tiny-mole [99]

Corrected Question

a. Develop a probability distribution for the job satisfaction score of a senior executive.

b. Develop a probability distribution for the job satisfaction score of a middle manager.

c. What is the probability a senior executive will report a job satisfaction score of 4 or 5?

d. What is the probability a middle manager is very satisfied?

Answer:

(c)0.83

(d)0.28

Step-by-step explanation:

The percent frequency distributions of job satisfaction scores os give below:

\left|\begin{array}{c|c|c}$Job Satisfaction Score&$IS Senior Executives(\%)&$IS Middle Managers(\%)\\1&5&4\\2&9&10\\3&3&12\\4&42&46\\5&41&28\end{array}\right|

(a)Probability distribution for the job satisfaction score of a senior executive.

\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_1(x))\\------&------\\1&0.05\\2&0.09\\3&0.03\\4&0.42\\5&0.41\end{array}\right|

(b)Probability distribution for the job satisfaction score of a middle manager.

\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_2(x))\\1&0.04\\2&0.10\\3&0.12\\4&0.46\\5&0.28\end{array}\right|

(c)Probability a senior executive will report a job satisfaction score of 4 or 5

P(a senior executive will report a job satisfaction score of 4 or 5)

=f_1(4)+f_1(5)\\=0.42+0.41\\=0.83

(d)Probability a middle manager is very satisfied

The probability a middle manager is very satisfied

=f_2(5)\\=0.28

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