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nikklg [1K]
2 years ago
8

Simplify. 10 / 7 k + 11 / 7 - 2 k + 2/7 + 2/7 k -6

Mathematics
1 answer:
Nikolay [14]2 years ago
6 0

As written, this is

\dfrac{10}{7}k+\dfrac{11}{7}-2k+\dfrac{2}{7}+\dfrac{2}{7}k-6=\left(\dfrac{10}{7}-2+\dfrac{2}{7}\right)k+\left(\dfrac{11}{7}+\dfrac{2}{7}-6\right)\\\\=\dfrac{10-14+2}{7}k+\dfrac{11+2-42}{7}\\\\=-\dfrac{2}{7}k-\dfrac{29}{7}

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Step-by-step explanation:

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7 0
3 years ago
A group of 59 randomly selected students have a mean score of 29.5 with a standard
algol [13]

Answer:

29.5-1.671\frac{5.2}{\sqrt{59}}=28.37    

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And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

Step-by-step explanation:

Information given

\bar X = 29.5 represent the sample mean

\mu population mean  

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The confidence interval for the true mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

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The Confidence interval is 0.90 or 90%, the significance is \alpha=0.1 and \alpha/2 =0.05, and the critical value is t_{\alpha/2}=1.671

Now we have everything in order to replace into formula (1):

29.5-1.671\frac{5.2}{\sqrt{59}}=28.37    

29.5+1.671\frac{5.2}{\sqrt{59}}=30.63    

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

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2 years ago
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Step-by-step explanation:

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