What is 3.25 reapting 5 as a fraction
1 answer:
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Answer:
Option C) We would reject the claim that the trains run late an average of 5 minutes and conclude that they run late an average of more than 5 minutes since the 99% confidence interval exceeds 5.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 5 minutes
Sample mean, = 9.130 minutes
Sample size, n = 10
Alpha, α = 0.01
Sample standard deviation, s = 1.4 minutes
First, we design the null and the alternate hypothesis
We have to construct 99% confidence interval.
99% Confidence interval:
Putting the values, we get,
99% Confidence interval: (7.6917,10.5683)
Since the population mean does not lie in he calculated confidence interval, thus, we fail to accept the null hypothesis and accept the alternate hypothesis.
Option C) We would reject the claim that the trains run late an average of 5 minutes and conclude that they run late an average of more than 5 minutes since the 99% confidence interval exceeds 5.
Answer:
It is degrees Fahrenheit when the crickets are chirping
times a minute.
Variables and
y-intercept
slope
Step-by-step explanation:
As the chirps are times per minute for
degrees Fahrenheit we will consider it in
.
Now when the chirps are times and temperature is
degrees we consider it
.
To find the slope we can use point-slope formula.
Where is the slope and
To find y-intercept we will plug out the value of slope in choosing point
.
So
And the equation is
To calculate temperature for chirpings we have to plug
and
in our above equation which is in form of
degrees Fahrenheit.
Finally we have :
Temperature degrees Fahrenheit.
With variables and
y-intercept and
slope