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3 years ago

X = 8 , m = 3 , EVAULATE !!!! ILL GIVE YOU BRAINLIST SHOW WORK !!!

Mathematics

2 answers:

UNO [17]3 years ago

8 0

Answer:

Step-by-step explanation:

$2(3x+6)\div(10m)\\\\x =8\\m =3\\\\2(3(8)+6)\div(10(3))\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(3\left(8\right)+6\right)\::\quad 30\\=2\times\:30\div \left(10\left(3\right)\right)\\\\\mathrm{Calculate\:within\:parentheses}\:\left(10\left(3\right)\right)\::\quad 30\\=2\times\:30\div \:30\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:2\times\:30\div \:30\:\\:\quad 2$

Stolb23 [73]3 years ago

5 0

Answer:

Step-by-step explanation:

plug it in

2(3(8)+6)/(10(3))

pemdas

2(24+6)/(30)

2(30)/(30)

60/30

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1. Find the value of x.<br><br> A. 90<br> B. 80<br> C. 60<br> D. 45

tia_tia [17]

Answer:

A 90

Step-by-step explanation:

multiple ways to prove this.

e.g. since the angle between the two lines from the center of the circle to the 2 tangent touching points is 90 degrees (that is the meaning of these 90 degrees here as the angle of the circle segment defined by the 2 tangent touching points and the circle center), the tangents have the same "behavior" as tan and cot = the tangents at the norm circle at 0 and 90 degrees. they hit each other outside of the circle again at 90 degrees.

another way

imagine the two right triangles of the tangents crossing point to the circle center and the tangent/circle touching points.

the Hypotenuse of each triangle is cutting the 90 degree angle of the circle segment exactly in half (due to the symmetry principle). so the angle between radius side and Hypotenuse is 90/2 = 45 degrees.

that means also the angle of such a right triangle at the tangent crossing point is 45 degrees (as the sum of all angles in a triangle must be 180, we have the remainder of 180 - 90 - 45 = 45 degrees).

the angles of both right triangles at that point are the same, and so we can add 45+45 = 90 degrees for the total angle at the tangent crossing point.

8 0

3 years ago

Jeff's math grade is based on two quizzes, two tests, and one project. The table shows Jeff’s scores on these items, as well as

vazorg [7]

Answer:

Step-by-step explanation:

If you can post the table then I'lI be happy to help

6 0

3 years ago

Read 2 more answers

Analyzing Graphs to Determine Input Values

miv72 [106K]

Answer:

Step-by-step explanation:

se the graph to determine the input values that

correspond with f(x) = 1.

O x=4

O x= 1 and x = 4

O x= -7 and x = 4

O x= -7 and x = 2

(-6, 4)

(1,4) w

(-7, 1)

(2, 1) x

-8/ -6 -4 -2

-2

-4

7 0

3 years ago

X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y

andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

$\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}$