Answer:
% Po lost = 100[1 - e^(-0.005t)] %; 73.0 g
Step-by-step explanation:
p(t) = 100e^(-0.005t)
Initial amount: p(0) = 100
Amount remaining: p(t) = 100e^(-0.005t)
Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]
% of Po lost = amount lost/initial amount × 100 %
= [1 - e^(-0.005t)] × 100 % = 100[1 - e^(-0.005t)] %
p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g
The mass of polonium remaining after 63 days is 73 g.
Answer:
70
Step-by-step explanation i subtracted but im not good at math so dont take my word for it
Okay so an in and out box is a box is basically a tale. Do you have a rule ? so if you have a rule..(which i do not know) lets say the rule is +2. lets also say that the IN says 4. Then what would be the out ? The out would be whatever 4+2 is. So basically the "out" is the outcome.
(8 p / h) * <u>"x"</u> h = p (in dollars).
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in which: "h" = hours ;
"p" = pay (in units of dollars);
"x" = number of hours.
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In the equation, on the left hand side, the unit symbol "h" would "cancel out" to "1" ;
and we would have:
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8 p * x = _<u>[total "p"]</u>__
