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3 years ago

5

The box-and-whisker plot represents the number of points scored by teams in a soccer league last year.

1 answer:

Yuki888 [10]3 years ago

3 0

C because a is incorrect and so is b and d

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Please help, I'm stuck on this question

vesna_86 [32]

Answer: Option C

$a> 0$

Step-by-step explanation:

The graph shows a radical function of the form $f(x)=a(x+k)^{\frac{1}{n}}+c$

Where n is a positive number.

For this type of function, if the coefficient $a> 0$ then then when x tends to $\infty$ f(x) tends to $\infty$ and when x tends to $-\infty$ then f(x) tends to $-\infty$ .

Notice in the graph that as x increases then f(x) also increases and as x decreases f(x) also decreases.

This indicates that the coefficient $a> 0$

5 0

3 years ago

The value of 2 in2,783 is what timesthe value of 2 in 7,283

VikaD [51]

The value of 2 in 2,783 is thousand. The value of 2 in 7,283, is hundred.
So it is one times the value.

6 0

3 years ago

Read 2 more answers

A circle is to be cut from a 12 ft square board. What will be the area, in square feet, of the inscribed circle? Leave your answ

Kazeer [188]

Answer:

3π sq.feet

Step-by-step explanation:

Area of the square = L²

L is the length of the square

Given

Area of the square = 12 ft square

12 = L²

L = √12

L = 2√3 feet

Since the circle is inscribed in the square, the length of the square will be the diameter of the circle;

Area of the circle = πd²/4

Area of the circle = π(2√3)²/4

Area of the circle = 12π/4

Area of the circle = 3π sq.feet

5 0

3 years ago

Write 3/25 as a percent

8_murik_8 [283]

100/25 = 4

4*3 = 12

The answer is 12%

Hope this helps! :)

3 0

3 years ago

A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer

Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

$L_A \to$ length of play area A

$W_A \to$ width of play area A

$L_B \to$ length of play area B

$W_B \to$ width of play area B

$x \to$ Area of A

$y \to$ Area of B

From the question, we have the following:

$L_A = 1 + 4W_A$

$W_B = 2 + W_A$

$L_B = 2 + 3W_B$

$x = y$

The area of A is:

$x = L_A * W_A$

This gives:

$x = (1 + 4W_A) * W_A$

Open bracket

$x = W_A + 4W_A^2$

The area of B is:

$y = L_B * W_B$

$y = (2 + 3W_B) * ( 2 + W_A)$

Substitute: $W_B = 2 + W_A$

$y = (2 + 3(2 + W_A)) * ( 2 + W_A)$

Open brackets

$y = (2 + 6 + 3W_A) * ( 2 + W_A)$

$y = (8 + 3W_A) * ( 2 + W_A)$

Expand

$y = 16 + 8W_A + 6W_A + 3W_A^2$

$y = 16 + 14W_A + 3W_A^2$

We have that:

$x = y$

This gives:

$W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2$

Collect like terms

$4W_A^2 - 3W_A^2 + W_A -14W_A - 16 =0$

$W_A^2 -13W_A - 16 =0$

Using quadratic calculator, we have:

$W_A = -14.1$ or $W = 1.13$ --- approximated

But the width can not be negative; So:

$W = 1.19$

7 0

2 years ago