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tankabanditka [31]
3 years ago
12

Please help i need both

Mathematics
1 answer:
Contact [7]3 years ago
5 0

Answer:

1. 10 inches 2. $7.70

Step-by-step explanation:

For number one they are simply multiplying the width by 2 and for the length, it would be 5 times 2 and you'll get 10 inches.

For number 2, you had to do 21 divided by 3 and get 7. Then find 10% of 21 which is 2.10. Then 2.10 divided by the three people is 0.7. So add 7 and .7 together and get $7.70

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How many times does the digit 7 appear among the terms of the sequence of consecutive integer numbers 7, 8, 9, ...., 777?
Dahasolnce [82]

Answer:

234 times

Step-by-step explanation:

<u>Number of times the number 7 appears in a hundred</u>

7 as units digit (07-17-27 ..... 97): 10 times

7 as tens digit (70-71-72..... 79): 10 times

20 times the digit 7 appears in first one hundred (0-100)

Let's calculate how many times 7 would be as units or tens in 7 hundreds

20X7 = 140 times digit 7 appears until number 699

<u>Now, from 700 to 777</u>

7 as hundreds digit (700-701-702 .... 777): 78 times

7 as tens digit (770-771-772 .... 777): 8 times

7 as units digit (707-717-727....777): 8 times

78 + 8 + 8 = 94 times the digit 7 appears in the range 700 - 777. Plus 140 times

140 + 94 = 234 times

4 0
3 years ago
Read 2 more answers
Explain in your own words what a transformation is.
dybincka [34]
A transformation is when something or someone goes through a physical or chemical change.


Please hope this helps
3 0
3 years ago
Which equation can be used to find what percent 14 is of 125?
IgorC [24]

Answer:

B. 14 = 125p

Step-by-step explanation:

6 0
3 years ago
Question 1<br> Which of the following statements is NOT true?
Olin [163]

Answer:

the bottom one

Step-by-step explanation:

They are both the same ab and bc but im not entirely  sure

4 0
3 years ago
Read 2 more answers
How do you solve this
Dmitriy789 [7]

By definition of the trig functions,

\sin30^\circ=\dfrac y{16}

\cos30^\circ=\dfrac x{16}

We have \sin30^\circ=\dfrac12, so y=8, and \cos30^\circ=\dfrac{\sqrt3}2, so x=8\sqrt3.

Just to check: we should have

x^2+y^2=16^2

by the Pythagorean theorem. Indeed,

8^2+(8\sqrt3)^2=4\cdot8^2=2^2(2^3)^2=2^8=(2^4)^2=16^2

6 0
4 years ago
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