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3 years ago

What are the excluded values v^2 +1 / v^2 -v-6

1 answer:

5 0

The rational expression
$\dfrac{v^{2}+1}{v^{2}-v-6}=\dfrac{v^{2}+1}{(v-3)(v+2)}$
will be undefined where the denominator is zero. Values of v that make the denominator zero are v=3 and v=-2.

Excluded values of v are -2 and 3.

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ITS SIMPLE USE THE CORDANITS LIKE 13-10 13 OVER 10 UP

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Write and solve a real-world additional problem including the sum of a rational number and it's additive inverse?

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3 years ago

Triangle MNO is an equilateral triangle with sides measuring 16 StartRoot 3 EndRoot units. Triangle M N O is an equilateral tria

Lesechka [4]

Answer:

The correct option is second one i.e 24 units.

Therefore the height of the triangle is

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Step-by-step explanation:

Given:

An equilateral triangle has all sides equal.

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$NM = MO = ON =16\sqrt{3}$

NR is perpendicular bisector to MO such that

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To Find:

Height of the triangle = NR = ?

Solution :

Now we have a right angled triangle NRM at ∠R =90°,

So by applying Pythagoras theorem we get

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Substituting the values we get

$(MN)^{2} = (MR)^{2}+(NR)^{2}\\\\(16\sqrt{3})^{2}=(8\sqrt{3})^{2}+(NR)^{2}\\\\(NR)^{2}=768-192=576\\Square\ rooting\ we\ get\\NR=\sqrt{576}=24\ units$

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3 years ago

Read 2 more answers

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Gala2k [10]

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3 years ago

Read 2 more answers

Need HELP PLS PIC ATTACHED

Vera_Pavlovna [14]

Answer:

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Step-by-step explanation:

(4x+5)(x-2)

Multiply each term in the first parenthesis by each term in the second (foil)

Step 1: Expand it by writing out each multiplication. I added a picture showing which order to do it. (go in order of green, red, blue, yellow.) (you can remember this as first, outside, inside, last.)

When you expand it'll look like: 4x⋅x+4x⋅-2-5x-5⋅-2

Step 2: Calculate product

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$4x^{2}$ +4x⋅-2-5x-5⋅-2

$4x^{2}$ +4x⋅-2-5x-5⋅-2 (4x⋅-2 becomes -8x) (multiply 4x times -2)

$4x^{2}$ -8x-5x-5⋅-2

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$4x^{2}$ -8x-5x+10

Step 3: collect like terms

$4x^{2}$ -8x-5x+10 (-8x-5x becomes -13x) (-8x times -5x)

$4x^{2}$ -13x+10 is the most simplified so it should be your final answer

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1 year ago