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maria [59]
4 years ago
5

What are the excluded values v^2 +1 / v^2 -v-6

Mathematics
1 answer:
valentina_108 [34]4 years ago
5 0
The rational expression
\dfrac{v^{2}+1}{v^{2}-v-6}=\dfrac{v^{2}+1}{(v-3)(v+2)}
will be undefined where the denominator is zero. Values of v that make the denominator zero are v=3 and v=-2.

Excluded values of v are -2 and 3.
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