Question

What are the excluded values v^2 +1 / v^2 -v-6

Answer 1

The rational expression
$\dfrac{v^{2}+1}{v^{2}-v-6}=\dfrac{v^{2}+1}{(v-3)(v+2)}$
will be undefined where the denominator is zero. Values of v that make the denominator zero are v=3 and v=-2.

Excluded values of v are -2 and 3.