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GenaCL600 [577]
3 years ago
13

Plot four lines. Each line should pass through the point

Mathematics
1 answer:
notka56 [123]3 years ago
3 0

Answer:

Step-by-step explanation:

I am on the same question

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Solve the system of equations using row operations. Write your answer in the form (x, y).
Sonja [21]

Answer:

(5, - 4 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = - 2 → (1)

3x - y = 19 → (2)

Multiplying (2) by 3 and adding to (1) will eliminate the y- term

9x - 3y = 57 → (3)

Add (1) and (3) term by term to eliminate y

(2x + 9x) + (3y - 3y) = (- 2 + 57), that is

11x = 55 ( divide both sides by 5 )

x = 5

Substitute x = 5 into either of the 2 equations and solve for y

Substituting into (1)

2(5) + 3y = - 2

10 + 3y = - 2 ( subtract 10 from both sides )

3y = - 12 ( divide both sides by 3 )

y = - 4

Solution is (5, - 4 )

8 0
3 years ago
PLease help me I'll give brainliest. ( Math )
dezoksy [38]

Answer:

they are multiplied by 9 on bottom

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can someone help me in this please???
MArishka [77]
The first one is 15 mornings
3 0
3 years ago
Read 2 more answers
Two brothers have a total age of 28 if one brother is older by 20 years how old is the second brother
svlad2 [7]

Answer:

8

Step-by-step explanation:

Total meaning addition, you would use the opposite operation to find the answer.  

28 - 20 = 8

And to check your work you would add;

20 + 8 = 28

which is the brothers total combined age.  

6 0
3 years ago
Read 2 more answers
Hello there can anyone solve this plz (chart is attached):
stich3 [128]

Answer:

h^\prime(1)=14

Step-by-step explanation:

We have the function:

h(x)=f[f(x)]

And we want to find:

h^\prime(1)

So, we will differentiate function <em>h</em>. By the chain rule, this yields:

h^\prime(x)=f^\prime[f(x)]\cdot f^\prime(x)

Then it follows that:

h^\prime(1)=f^\prime[f(1)]\cdot f^\prime(1)

Using the table, we acquire:

h^\prime(1)=f^\prime(3)\cdot2

And using the table again, we acquire:

h^\prime(1)=7\cdot 2

Evaluate. Hence:

h^\prime(1)=14

6 0
3 years ago
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