Answer:
A.O(1)
Explanation:
In the implementation of queue by using linked chain the performance of the enqueue operation is O(1).We have to maintain two pointers one head and the other tailand for enqueue operation we have to insert element to the next of the tail and then make that element tail.Which takes O(1) time.
Answer:
The code to this question can be given as:
Code:
while ((s!="Y" && s!="y" && s!="N" && s!="n")) //loop for check condition
{
cin >> s; //insert value
}
Explanation:
The description of the following code:
- In this code, we use a string variable s that has been to define in question.
- In code, we use a while loop. It is an entry control loop in loop we check variable s value is not equal to "y", "Y", "n" and "N".
- In the loop we use AND operator that checks all value together. If this is true So, we insert value-form user input in string variable that is "s".
It's GigaBytes actually. And is it RAM or storage capabilities?
And also those are brands. Not models. For example, Samsung has different phones. Not just one.
Idek but hope u figure it out!
