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nydimaria [60]
4 years ago
7

What technique creates different hashes for the same password? ccna routing protocols final answers?

Computers and Technology
1 answer:
elena-s [515]4 years ago
7 0
The answer is Salted Password Hashing.  The process is similar to hashing., but with a twist. A random value is introduced for each user. This salt value<span> is included with the password when the hash value is calculated and is stored with the user record. Including the salt value means that two users with the same password will have different password hashes.</span>
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An oil slick occurs when an underwater refinery pipe ruptures, pumping oil into the water. The spilled oil sits on top of the wa
yaroslaw [1]

Answer:

Here the code is given as follows,

Explanation:

#include <iostream>

#include <iomanip>

using namespace std;

const double CUBIC_CENTIMETERS_IN_ONE_GALLON = 3785.41;

const double CENTIMETERS_IN_ONE_KILOMETER = 100000.00;

double oilSlickArea(double oilThick,

double oilReleasedRate, double spilTimeInHours);

int main()

{

double oilThickness;

double oilReleasedGallonsPerMinute;

int slickDays;

double spillArea = 0.0;

cout << fixed << showpoint << setprecision(8);

cout << "Enter the oil spill rate per minute (in gallons): ";

cin >> oilReleasedGallonsPerMinute;

cout << endl;

cout << "Enter oil thickness on top of the water (in centimeters): ";

cin >> oilThickness;

cout << endl;

cout << "Enter the number of days for which you want to know "

<< "the area covered by the spilled oil: ";

cin >> slickDays;

cout << endl;

cout << "Oil slick area after each day for " << slickDays << "days."

<< endl << endl;

cout << setw(5) << " " << setw(20) << left << "Slick Area in"

<< setw(20) << left << " Volume of Oil in" << endl;

cout << setw(5) << left << "Day " << setw(20) << left << "Square Kilometers"

<< setw(20) << left << " in Gallons" << endl;

for (int i = 1; i <= slickDays; i++)

{

spillArea = spillArea + oilSlickArea(oilThickness,

oilReleasedGallonsPerMinute, 60 * 24);

cout << setw(4) << left << i << " " << setw(12)

<< setprecision(8) << spillArea / (CENTIMETERS_IN_ONE_KILOMETER * CENTIMETERS_IN_ONE_KILOMETER)

<< " " << setprecision(2)

<< right << setw (15) << (oilReleasedGallonsPerMinute * 60 * 24 * i) << endl;

}

return 0;

}

double oilSlickArea(double oilThick,

double oilReleasedRate, double spilTimeInHours)

{

double oilVolumeInGallons;

double oilVolumeInCubicCentimeters;

double spillArea;

oilVolumeInGallons = oilReleasedRate * spilTimeInHours;

oilVolumeInCubicCentimeters = oilVolumeInGallons * CUBIC_CENTIMETERS_IN_ONE_GALLON;

spillArea = oilVolumeInCubicCentimeters / oilThick;

return spillArea;

}

8 0
3 years ago
In this paper https://arxiv.org/pdf/2008.10150.pdf, I'm having a hard time understanding how the assignment in the picture is de
anastassius [24]

Answer:

f*(i,z) = log pxz

Explanation:

they round

4 0
3 years ago
Read 2 more answers
The determination of the overall system architecture consisting of a set of physical processing components, hardware, software,
Masteriza [31]

Answer:

Systems engineering is the process of planning, designing, and implementing a system or systems.

7 0
2 years ago
a cisc-style instruction set has a large number of high-level instructions that perform highly complex operations in a single st
NikAS [45]

Both desktop and laptop computers employ CISC (complex instruction set computer) CPUs. Small programs are on CISC machines. It requires a lot of time to execute because it contains a great deal of compound instructions.

<h3>What do you mean by CISC?</h3>

Both desktop and laptop computers employ CISC (complex instruction set computer) CPUs. More complex instructions can be processed by this kind of CPU. For instance, a single instruction might load two values, add them, and then store the outcome back in memory.

A computer that, in contrast to a computer with a limited instruction set, allows individual instructions to perform numerous processes and need a large number of cycles to complete (RISC).

Small programs are on CISC machines. It requires a lot of time to execute because it contains a great deal of compound instructions. In this case, a single set of instructions is safeguarded in stages; each instruction set contains more than 300 distinct instructions. On average, instructions take two to ten machine cycles to complete.

To learn more about CISC refer to:

brainly.com/question/13266932

#SPJ4

8 0
2 years ago
Write a full class definition for a class named Player , and containing the following members:
Paraphin [41]

Answer:

I used C++ to implement this program using dev c++, however, i defined the public method inside the class. The code with illustration of this question is given in section phase. If you want to define the classes outside from class then you can use scope resolution operator to access the method of the class. However, the complete running code is given below in <em>explanation </em>section

Explanation:

#include <iostream>// included preprocessor directive

using namespace std;

class player// class player is started from here

{

private:// class varaibles are set at here and scope of varialbe is private.

 string name;//variable for getting and setting name of player

 int score;//variable for getting and setting score of player

 

public:// declaring public method that can be accessbile outside of class but in this program

 void setName (string name)// public method for setting name of player

{

 this->name=name;// name is initialized by paramenter name to variable name

}

 void setScore(int score)//publice method for setting score of player

{

 this->score=score;

}

int getScore()// public method for getting score of player

{

 return score;// on call, return the score of player

}

string getName()// public method for getting name of player

{

 return name;// return player name;

}

 

};//end of class "player"

int main()//main function get executed

{

   player firstPlayer;//class object "firstPlayer" is created

firstPlayer.setName("Renaldo");// firstPlayer name is initialized

firstPlayer.setScore(500);// assgined score to firstPlayer

string getname=firstPlayer.getName();// get name of firstPlayer

int getscore=firstPlayer.getScore();//get score of firstPlayer

cout<<getname;//print name of firstPlayer

cout<<"\n";//line break

cout<<getscore;//print score of firstPlayer

cout<<"\n";//line break

   

   return 0;//end of program

}

6 0
3 years ago
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