What is the vertex of the graph of y = 5(x + 4)2 + 3?

2 answers:

6 0

The vertex form: y = a(x - h)² + k

(h; k) - coordinates of the vertex

Therefore:

y = 5(x + 4)² + 3
vertex: (-4; 3)

Answer: A: -4, 3

vovikov84 [41]3 years ago

4 0

A: -4,3 The x coordinate of the vertex is given by x = -b/2a and the y coordinate of the vertex is given by y= f( -b/2a), we need to transform the equation to the form ax^2 + bx + c We have: 5(x+4)^2+3 = 5x^2+ 20x + 23 Then we substitute x= -20/2*5 y= f(-20/2*5) = -4 = f(-4) =3 So V(-4,3)

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Suppose EG=3, EB=8, A(F)=7, m∠EBG=23, m∠EGF=32, and m∠CAE=51. Find m∠CAF.

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m∠CAF is 28°

Step-by-step explanation:

The given parameters are;

EG = 3, EB = 8, A_F = 7, m∠EBG = 23°, ∠EGF 32°, and m∠CAE = 51°

From the diagram, we have;

m∠EBG = m∠EAD ; ${}$ Given

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Therefore, we have;

51° = m∠CAF + 23° ${}$

m∠CAF = 51° - 23° ${}$

m∠CAF = 28°

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