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3 years ago

What is -18+6+3r+13r=

1 answer:

7 0

If this is just an expression, then all you have to do is combine like terms, or groups of numbers and variables that have the same variable.

When simplified, you get the equation

-12+ 16r or

-18+6+3r+13r=16r-12

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find the equation of the line passes through the point (-1,2) and making an angle of 45° with the line x-y+1=0

Vlad1618 [11]

Answer:

Step-by-step explanation:

line given is x-y+1= 0

you can rewrite it in slope intercept y=mx+b where m is the slope, and b is the y-intercept where the line meets the y-axis

x-y+1 =0 subtract x and 1 from both sides of the equation

-y = -x-1 multiply both sides by -1

y = x+1 so the slope of this line is 1 and the y-intercept is 1

If you draw this line you can see that there are actually 2 lines that form 45° angles with y=x+1 and pass through (-1, 2), one is vertical x= -1 and one horizontal y =2

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3 years ago

What is the probability of you picking a weekend day from the days of the week?

svet-max [94.6K]

Answer:

3/7

Step-by-step explanation:

its 3/7 because there are 3 weekend days and there are 7 days in total in one week, so out of the week there is 3 weekend days.

i hope this helps :)

6 0

3 years ago

What are the x-intercepts of the graph

faltersainse [42]

there is no graph here to answer this

7 0

3 years ago

The oven tray is 600mm by 500mm. A cake tin is 25cm in diameter. How many cake tins can jenny fit on the oven tray at one time?

vlada-n [284]

Area of Circle= $\pi 
$ $r^{2}$
= $\frac{22}{7}$ x $( \frac{25cm}{2}) ^{2}$
= 490.87 $cm^{2}$

Area of Oven tray= 60cm x 50cm
= 3000 $cm^{2}$

: . # tin that can hold on bake tray= 3000 $cm^{2}$ / <span>490.87 $cm^{2}$ = 6.11
Thus making it logically 6..... </span>

8 0

3 years ago

You spin the spinner shown below once. Each sector shown has an equal area.

a_sh-v [17]

Answer: P(not shaded sector) = 0.50

Step-by-step explanation:

Since we have given that

Number of shaded parts = 6

Number of unshaded parts = 6

Total parts = 6+6 = 12

So, Probability of getting not shaded sector is given by

$\dfrac{6}{12}\\\\=\dfrac{1}{2}\\\\=0.50$

Hence, P(not shaded sector) = 0.50

8 0

3 years ago