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Arturiano [62]
3 years ago
5

Which ratio represents sin A? a) 8/17 b) 15/17 c) 17/15 d) 17/8

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0
The picture in the attached figure

we know that
in the right triangle ABD
AB²=BD²+AD²-----> BD²=AB²-AD²
AB=8
AD=64/17
BD²=8²-(64/17)²----> 64-(4096/289)----> BD²=14400/289
BD=√(14400/289)-----> BD=120/17

sin A=BD/AB-----> sin A=(120/17)/8----> 15/17

the answer is
15/17

n200080 [17]3 years ago
3 0

Answer:

b) 15/17

Step-by-step explanation:

Notice that ΔABD is a right triangle with AB the hypotensue. The sine of an angle is the ratio of

opposite leg

hypotenuse

. In ΔABD you can solve for the opposite leg (BD) using the Pythagorean Theorem.

BD2 + [64/17)2 = 82

BD =

120

17

. Therefore, sin A =

15

17

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Solve for x.

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 x = -4/3y² -40/3y -103/3 . . . . 'standard form' in the US

__

Taking our clues from the graph*, we can write the vertex form equation as ...

 x = -4/3(y +5)² -1 . . . . . . 'standard form' in other places

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* The vertex is (-1, -5), so for some leading coefficient, the equation will be ...

 x = a(y -(-5))² +(-1) = a(y +5)² -1

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