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3 years ago

Which action by the body best releases heat and cools the body during and after exercising?

Mathematics

2 answers:

Alborosie3 years ago

8 0

Answer:

Step-by-step explanation:

olchik [2.2K]3 years ago

4 0

Answer:

Step-by-step explanation:

B , becausse when percipitation occurs you sweat which is how your body releases heat and cools you down.

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Give abc =jkl,m<b=55 and m<L=25 what is the measure of <j

Irina18 [472]

I really don’t know but I think I got it wrong

4 0

3 years ago

Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withd

zysi [14]

Answer:

a) $520

b) $580

c) Interest amount is same each year

Step-by-step explanation:

Given - Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withdrawals.

To find - a) How much money was in the account after one year?

b) How much money was in the account after 4 years?

c) Was the amount of money earned in interest the same or different each year?

Proof -

Here given that,

Principal amount = $500

rate of interest = 4% = 4/100 = 0.04

Now,

Amount = P [ 1 + RT ]

= 500 [ 1 + 0.04(1)]

= 500 [ 1 + 0.04] = 520

⇒Amount = $520

Amount = P [ 1 + RT ]

= 500 [ 1 + 0.04(4)]

= 500 [ 1 + 0.16] = 580

⇒Amount = $580

In 2nd year,

Amount = P [ 1 + RT ]

= 500 [ 1 + 0.04(2)]

= 500 [ 1 + 0.08] = 540

⇒Amount = $540

Now,

Interest in 1st year = 520 - 500 = 20

Interest in 2nd year = 540 - 520 = 20

So,

The interest amount is same each year

3 0

3 years ago

Toby pulled weeds and earned $22.50 for three hours of work. How much will he earn tomorrow if he works for 2 hours?

postnew [5]

How many hours total?

8 0

2 years ago

Read 2 more answers

What's the slope of y=-x+3

Reika [66]

The slope would be -1 since it’s the coefficient of -x

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3 years ago

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Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

where $0\le r\le2$ and $0\le\theta\le2\pi$ .

The integral along the surface of the cylinder (with outward/positive orientation) is then

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

7 0

3 years ago