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iren [92.7K]
3 years ago
15

Which action by the body best releases heat and cools the body during and after exercising?

Mathematics
2 answers:
Alborosie3 years ago
8 0

Answer:

A

Step-by-step explanation:

olchik [2.2K]3 years ago
4 0

Answer:

b

Step-by-step explanation:

B , becausse when percipitation occurs you sweat which is how your body releases heat and cools you down.

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A coyote is walking at 2m/s and sees a rabbits and reaches a speed of 26 m/s in 6 seconds. What is the acceleration of the coyot
yulyashka [42]

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4m/s2

Step-by-step explanation:

6 0
3 years ago
each morning a gardener uses 24 3/4 gallons of water from a barrel. each afternoon, she adds 15 1/4 gallons of water to the barr
Nimfa-mama [501]

Answer:

47\frac {1}{2}\ gallons

Step-by-step explanation:

Assuming that the tank is only for agricultural use, also no significant leakages then at the end of the day, the amount consumed will be equivalent to 24\frac {3}{4}-\ 15\frac {1}{4}=9\frac {1}{2}

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6 0
3 years ago
Professor Halen teaches a College Mathematics class. The scores on the midterm exam are normally distributed with a mean of 72.3
lbvjy [14]

Answer:

14.63% probability that a student scores between 82 and 90

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 72.3, \sigma = 8.9

What is the probability that a student scores between 82 and 90?

This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So

X = 90

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 73.9}{8.9}

Z = 1.81

Z = 1.81 has a pvalue of 0.9649

X = 82

Z = \frac{X - \mu}{\sigma}

Z = \frac{82 - 73.9}{8.9}

Z = 0.91

Z = 0.91 has a pvalue of 0.8186

0.9649 - 0.8186 = 0.1463

14.63% probability that a student scores between 82 and 90

3 0
3 years ago
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