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Andreyy89
4 years ago
8

Compare using <, =, or >. –1.23 _____ –1.25

Mathematics
2 answers:
NARA [144]4 years ago
7 0
Its the arrow that opens to the right
andre [41]4 years ago
5 0
You would use the "greater than" symbol to compare these numbers. >
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Please help me i am desperate please (1/3)
Sergeu [11.5K]

I think we're not supposed to do more than 3 problems in one answer; certainly not five pages. Does the 1/3 mean there are 10 more to come?

I'll do the first page.

6)

Right triangle, opposite side of 10, adjacent side of 21,

tan x = opp/adj = 10/21

x = arctan 10/21 = 25.46°

Answer: 25

7)

cos x =   adj / hyp = 10/14

x = arccos 10/14 = 44.42°

Answer: 44

8)

tan x = opp/adj = 12/24 = 1/2

x = arctan 1/2 = 26.57°

Answer: 27

9)

tan x = 31/32

x = arctan 31/32 = 44.09°

Answer: 44

10)

x = arctan 10/27 = 20.32°

Answer: 20

8 0
3 years ago
Ok her it is need help
Furkat [3]

Answer:

..........

Step-by-step explanation:

5 0
3 years ago
Which expression is not equivalent to?​
grigory [225]

C would be the answer. When you simplify the equations C does not contain a radical.

3 0
3 years ago
The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
The local monsters are currently throwing a bash
sammy [17]

Answer: 55 minutes

Step-by-step explanation:

First, you would have to subtract 5 from 225 because there are already 5 monsters there.

225-5= 220

Next, you would have to divide 220 by 4 to find the amount of minutes.

220/4= 55

6 0
3 years ago
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