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ivanzaharov [21]
3 years ago
10

Use a proportion to find the whole 95 is 20% of what number?

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
7 0
95           x
-----   =   ------
20           100

x is equal to 475
m_a_m_a [10]3 years ago
6 0
95 is 20% of 475
to check answer do 475 times .2
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A newborn mouse weighs about 0.25 ounce. A newborn cat weighs about 4 ounces. A new born cat weighs how many times as much as a
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2 years ago
Solve each equation mentally.
larisa [96]

Answer:

1) 1/17

2) 1/111

3) 1/15

They're all fractions

Hope that helped, just divide the result with the number available

Example :

1÷17 =1/17

4 0
3 years ago
Help please I get y=mx+b but I'm not sure how to do this
Fofino [41]

(3,4)  (9,7)

to find the slope

m = (y2-y1)/(x2-x1)

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3/6

1/2

The slope is 1/2

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y-y1 = m(x-x1)

y-4 = 1/2(x-3)

distribute

y-4 = 1/2x -3/2

add 4 to each side

y = 1/2 x -3/2 + 4

y = 1/2 x -3/2 + 8/2

y = 1/2 x + 5/2

this is in slope intercept form

8 0
3 years ago
Read 2 more answers
About 1,400,000 people live in a city. The city has a land area of 320 square miles. What is the city's population density (peop
Evgen [1.6K]

Answer:

the population ia 4,375 people per square mile

Step-by-step explanation:

7 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
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