Number 1 is 401
number 2 is 404.91
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Y = 4x - 1
The slope here is “4”
B)
2x6= 12
2x7= 14
2x8= 16
2x8= 18
Answer:
c
Step-by-step explanation:
Since both equations express y in terms of x we can equate the right sides
3x + 5 = - x + 3 ( add x to both sides )
4x + 5 = 3 ( subtract 5 from both sides )
4x = - 2 ( divide both sides by 4 )
x = - 0.5
substitute x = - 0.5 in either of the 2 equations
using y = - x + 3 then y = 0.5 + 3 = 3.5
solution is (- 0.5, 3.5 ) → c
Let c represents the cost of a candy apple and b represents the cost of a bag of peanuts.
Darius can purchase 3 candy apples and 4 bags of peanuts. So his total cost would be 3c + 4b. Darius can buy 3 candy apples and 4 bags of peanuts in $11.33,so we can write the equation as:
3c + 4b = 11.33 (1)
Darius can purchase 9 candy apples and 5 bags of peanuts. So his total cost would be 9c + 5b. Darius can buy 9 candy apples and 5 bags of peanuts in $23.56,so we can write the equation as:
9c + 5b = 23.56 (2)
<span>Darius decides to purchase 2 candy apples and 3 bags of peanuts. The total cost in this case will be 2c + 3b. To find this first we need to find the cost of each candy apple and bag of peanuts by solving the above two equations.
Multiplying equation 1 by three and subtracting equation 2 from it, we get:
3(3c + 4b) - (9c + 5b) = 3(11.33) - 23.56
9c + 12b - 9c - 5b = 10.43
7b = 10.43
b = $1.49
Using the value of b in equation 1, we get:
3c + 4(1.49) = 11.33
3c = 5.37
c = $ 1.79
Thus, cost of one candy apple is $1.79 and cost of one bag of peanuts is $1.49.
So, 2c + 3b = 2(1.79) + 3(1.49) = $ 8.05
Therefore, Darius can buy 2 candy apples and 3 bags of peanuts in $8.05</span>