The difference would be 74.059
Answer:
m∠P =119
m∠Q = 61
Step-by-step explanation:
m∠P = 2(∠Q)-3 or p=2(q)-3
supplementary angles so they combine to equal 180!
soooooo we can take
q+p=180
input what p equals and you get
q+ 2(q)-3=180
3q-3=180
3q=183
q=61
now we have what m∠Q is, so just subtract that from 180 to get m∠P
180-61=119
Answer:
17 nickles !
Step-by-step explanation:
First, identify the variables:
n = amount of nickels
d = amount of dimes
Next, setup the equations based on what you know. The first equation is:
n + d = 28
For the second equation, we know that a dime is worth 10¢ and a nickel is 5¢, so it should be:
0.05n + 0.10d = 1.95
This a three-step answer:
In one formula (you can use any of them; most people use the simplest one), single out the variable on one side
Apply the first formula into the second formula, and solve it to get the value of one variable
Apply the answer from the second formula into the first formula, and solve it to get the value of the other variable
======
Step One:
n + d = 28
n + d - d = 28 - d
n = 28 - d
Step Two:
0.05n + 0.10d = 1.95
(0.05 * (28 - d)) + 0.10d = 1.95
1.40 - 0.05d + 0.10d = 1.95
1.40 + 0.05d = 1.95
1.40 - 1.40 + 0.05d = 1.95 - 1.40
0.05d = 0.55
d = 11
Step Three:
n = 28 - d
n = 28 - 11
n = 17
======
Your answer should be 17 nickels and 11 dimes.
You can double check by applying the variables into both formulas.
n + d = 28
17 + 11 = 28
28 = 28
0.05n + 0.10d = 1.95
(0.05 * 17) + (0.10 * 11) = 1.95
0.85 + 1.10 = 1.95
1.95 = 1.95
I hope this helped.
ANSWER
No real roots.
The roots are complex or imaginary.
EXPLANATION
The quadratic equation
has discriminant,
If the discriminant is less than zero , then the quadratic equation has no real roots.
The given discriminant is -9.
Since -9 is less than zero, it means the quadratic equation has complex or imaginary roots.
Answer:
13) 
⇒ ![\frac{1}{\sqrt[4]{(5x)^5}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%5B4%5D%7B%285x%29%5E5%7D%7D)
15) 
⇒ 
Step-by-step explanation:
Given expression:
13)
15)
Write the expressions in radical form.
Solution:
For an expression with exponents as fraction like
the numerator 
represents the power it is raised to and the denominator 
represents the nth root of the expression.
For an expression with exponents as negative fraction like
We take the reciprocal of the term by rule for negative exponents.
So it is written as:
using the above properties we can write the given expressions in radical form.
13)
⇒ 
[Using rule of negative exponents]
⇒ [writing in radical form]
15)
⇒ [Since 2nd root is given as 
in radical form]
