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tankabanditka [31]
3 years ago
13

Simplify completely quantity of x squared plus 7 x minus 30 all over quantity of x plus 10. x2 + 4 x2 ? 4 x ? 3 x + 3

Mathematics
2 answers:
Solnce55 [7]3 years ago
6 0

Answer:

(x-3)

Step-by-step explanation:

\frac{x^2+7x-30}{x+10}

To divide it, we need to factor the numerator

lets factor x^2+7x-30

product is -30 and sum is 7

we need to find out two factors whose product is -30 and sum is 7

10 \cdot (-3)= -30

10-3=7

x^2+7x-30

(x+10)(x-3)

Replace it in the denominator

\frac{x^2+7x-30}{x+10}

\frac{(x+10)(x-3)}{x+10}

cancel out x+10

(x-3)

GalinKa [24]3 years ago
4 0

This looks like: \frac{x^2+7x-30}{x+10}

To solve this problem, you'll want to use the AC method to factor x^2+7x-30.

After factoring your expression will look like this:

\frac{(x-3)(x+10)}{x+10}

Cancel out the x+10 because they are common factors, so you are just left with the simple x-3.

Answer is:

x - 3

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Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro
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Answer:

The missing side is B = 6.0\ cm

The missing angles are \alpha = 56.2 and \theta = 93.8

Step-by-step explanation:

Given

A = 10\ cm

C = 12\ cm

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The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with \alpha

Angle B with \beta

Angle C with \theta

Calculating B

This will be calculated using cosine formula as thus;

B^2 = A^2 + C^2 - 2ACCos\beta

Substitute values for A, C and \beta

B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30

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B^2 = 36.2

Take Square root of both sides

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This will be calculated using cosine formula as thus;

A^2 = B^2 + C^2 - 2BCCos\alpha

Substitute values for A, B and C

A^2 = B^2 + C^2 - 2BCCos\alpha

10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha

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Collect Like Terms

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Divide both sides by -144

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C^2 = B^2 + A^2 - 2BACos\theta

Substitute values for A, B and C

12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta

144 = 36 + 100 - 120Cos\theta

Collect Like Terms

144 - 36 - 100 = -120Cos\theta

8 = -120Cos\theta

Divide both sides by -120

\frac{8}{-120} = Cos\theta

-0.0667= Cos\theta

\theta = cos^{-1}(-0.0667)

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