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lord [1]
3 years ago
12

A square has an area of 64 square units. A cube has a volume of 64 cubic units. What is the difference in the side length of the

square and the length of one edge of the cube?
Mathematics
1 answer:
Rina8888 [55]3 years ago
4 0
The formula in solving the area of a square is Area = a² where "a" is for the length of the side. The area formula in solving a cube is Area = 6a² where "a" is for the length of its side.
Area of square = a²
64 = a²
a = 8 units

Area of cube = 6a²
64= 6a²
a = 3.27 units 

The difference of side of the square and side of the cube is shown below:
Difference = 8 - 3.27
Difference = 4.73 units.

The answer is 4.73 units.
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Step-by-step explanation:

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(x, y) is given: (4, 7)

plug in values and solve for b:

7 = (1)(4) + b

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Ket [755]
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5 0
4 years ago
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lisov135 [29]

Answer:

S1) False. 2³ is 2 × 2 × 2 which is <u>8, not 6.</u>

S2) False. ( 2x / 3y ^ (2) ) ^ (3) =

( (2x) ^ (3) / ( (3y) ^ (2) ) ^ (3) ) = (2)³ × (x)³ / (3)³ × (y²)³ = 8 × x³ / 27 × y<u>⁶</u> = 8x³ / 27y<u>⁶</u><u>.</u>

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6 0
3 years ago
The perimeter of a rectangle is 102 cm. If the length is 15 cm less than twice the width , what are the dimensions?
lianna [129]
Let the length be \ell and the width be w. Now, write the length in terms of the width. "The length is 15 cm. less than twice the width" in the form of an equation is

\ell = 2w - 15 cm.

Let's plug that into the equation for the perimeter now. The perimeter of a rectangle is 2 \ell + 2w, so the equation for the perimeter of this rectangle is

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Plugging in the length in terms of width and solving for the width, we get

2(2w - 15 cm.) + 2w = 102 cm.
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To find the length, we just have to plug in the width into the equation we wrote for the length in terms of the width:

\ell = 2w + 15 cm.
\ell = 2(22 cm.) - 15 cm.
\bf \ell = 29 cm.
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3 years ago
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