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victus00 [196]
3 years ago
8

How many distinct zeroes does the function

B2%29%5C%5C" id="TexFormula1" title="f(x)=(2x+1)(x+1)(5x-4)(2x+2)\\" alt="f(x)=(2x+1)(x+1)(5x-4)(2x+2)\\" align="absmiddle" class="latex-formula"> have?
Mathematics
1 answer:
irina [24]3 years ago
6 0

It has 3 zeroes which are

\frac{-1}{2}, -1, \frac{4}{5}

Hope this helped!

~Just a girl in love with Shawn Mendes

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timama [110]
2x+3-5.32=68.82

2x= 71.14

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3 years ago
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The profitability, P, of a popular restaurant franchise can be modeled by the function P (t) = t4 – 10t3 + 28t2 – 24t, where t i
vekshin1

In this question, the profit of the restaurant after t months is given by a polynomial function. To find when it begins to show a profit, we find the numerical values of the function for t, and it shows a profit when t > 0

Profit after t months:

P(t) = t^4 - 10t^3 + 28t^2 - 24t

0 months:

This is P(0). So

P(0) = 0^4 - 10*0^3 + 28*0^2 - 24*0 = 0

1 month:

This is P(1). So

P(1) = 1^4 - 10*1^3 + 28*1^2 - 24*1 = -5

2 months:

This is P(2). So

P(2) = 2^4 - 10*2^3 + 28*2^2 - 24*2 = 0

3 months:

This is P(3). So

P(3) = 3^4 - 10*3^3 + 28*3^2 - 24*3 = -9

4 months:

This is P(4). So

P(4) = 4^4 - 10*4^3 + 28*4^2 - 24*4 = -32

5 months:

This is P(5). So

P(5) = 5^4 - 10*5^3 + 28*5^2 - 24*5 = -45

6 months:

This is P(6). So

P(6) = 6^4 - 10*6^3 + 28*6^2 - 24*6 = 0

7 months:

This is `P(7). So

P(7) = 7^4 - 10*7^3 + 28*7^2 - 24*7 = 175

After 7 months it shows profit, so it starts showing profit on the 6th month, and thus, the correct answer is given by option D.

For another example of a function involving numeric value, you can check brainly.com/question/24231879

8 0
3 years ago
3^3 . x^2- 25 divided by 5 when x= 0.6
Alenkasestr [34]

Hey there!

3^3 * x^2 - 25 / 5

= 3^3 * 0.6^2 - 25 / 5

= 3 * 3 * 3 * 0.6 * 0.6 - 25 / 5

= 9 * 3 * 0.6 * 0.6 - 25 / 5

= 27 * 0.36 - 25 / 5

= 9.72 - 25 / 5

= 9.72 - 5

= 4.72


Therefore, your answer is: 4.72


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

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Answer:

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