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victus00 [196]
2 years ago
8

How many distinct zeroes does the function

B2%29%5C%5C" id="TexFormula1" title="f(x)=(2x+1)(x+1)(5x-4)(2x+2)\\" alt="f(x)=(2x+1)(x+1)(5x-4)(2x+2)\\" align="absmiddle" class="latex-formula"> have?
Mathematics
1 answer:
irina [24]2 years ago
6 0

It has 3 zeroes which are

\frac{-1}{2}, -1, \frac{4}{5}

Hope this helped!

~Just a girl in love with Shawn Mendes

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Find the area of the compound shape
andrey2020 [161]
This shape is separated into two trapezoids. The equation for the area of a trapezoid is .5(base1 + base2) multiplied by height. Therefore, each half of the compound shape would be equal to .5(12 + 8) * 6 or 10 * 6 = 60. So the area of the total would be 60+60 or 120.
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3 years ago
Solve for x in the diagram below
ella [17]

Answer:

20

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3x + x + 100 = 180 (sum of angles on a straight line)

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3 years ago
1/4 = x/12 solve for x
Vedmedyk [2.9K]
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6 0
2 years ago
HELPPPP DUE SOON!!! WILL MARK BRAINLYIST AND 10 POINTS
larisa86 [58]

Answer:

688.7

Step-by-step explanation:

Top and Bottom

Area = 3/4 * pi * r^2

r = 6

Area = 3/4 * 3.14 * 6^2

Area =                                                               84.78

Don't round yet.

Vertical surface

Vertical surface = 3/4 * pi * d * h

d = 12 inches (the diameter)

Vertical surface = 3/4 * 3.14 * 12 * 15

Vertical surface =                                          423.9

Two inner faces

They are both rectangles

Area = 2 * L * W

L = 15

w=6

Area = 2 * 15 * 6                           <u>                  180</u>

Total                                                               688.68

Total = 688.7

7 0
2 years ago
Item 5
Sedbober [7]

Answer: 300.3858/ maybe 300.385

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3 0
2 years ago
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