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3 years ago

Find bc to the nearest tenth

Mathematics

1 answer:

egoroff_w [7]3 years ago

6 0

Answer:

BC ≈ 3.3

Step-by-step explanation:

Using the tangent ratio in the right triangle.

tan A = $\frac{opposite}{adjacent}$ , that is

tan20° = $\frac{BC}{AB}$ = $\frac{BC}{9}$ ( multiply both sides by 9 )

9 × tan20° = BC , then

BC ≈ 3.3 ( to the nearest tenth )

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Please help me solve this

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Answer:

1st pic:

x = 49

top angle = 45

bottom angle = 108

far right angle = 27 degrees

2nd pic:

angle 1 = 88 degrees

angle 2 = 57 degrees

angle 3 = 35 degrees

angle 4 = 145 degrees

Step-by-step explanation:

1st pic:

you can find the far right angle by taking 153 and subtracting it from 180:

⇒ 180 - 153 = 27 degrees

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top angle : x - 4

49 - 4 = 45 degrees

bottom angle: 2x + 10

2 x 49 + 10 = 108 degrees

2nd pic:

angle 1:

⇒ 180 - 92 = 88 degrees

angle 2:

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angle 3:

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j(1) = f(1) = 2

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j'(1) = f'(1) = 3

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j(x) = 1/f(x)

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