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frozen [14]
3 years ago
5

A population of 240 animals decreases at an annual rate of 10%. Find the multiplier for the rate of exponential decay. a. 1.9. b

. 0.9. c. 0.1. d. 1.1.
Mathematics
2 answers:
german3 years ago
6 0
If the population of the animals decreases by 10% every year. This means that the population for the next year is 90% of that in the previous. The multiplier for the rate of exponential decay is therefore 0.90. The answer is letter B. 
Tpy6a [65]3 years ago
6 0

Answer: . b. 0.9

Step-by-step explanation:

The general exponential decay function is given by :-

f(x)=A(1-r)^x, where A is the initial valuye , r i sthe rate of decay and x is time period.

The multiplicative rate of exponential decay is given by :-

b=1-r

Given: the rate of decay = 10 % = 0.1

Then , the multiplier for the rate of given exponential decay will be :-

1-0.1=0.9

Hence, the the multiplier for the rate of given exponential decay=0.9

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Step-by-step explanation:

take (1,3) and (9,7)

slope=(7-3)/(9-1)=4/8=1/2

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3 years ago
Pls Help: I need help
Anna11 [10]

Answer: C

Step-by-step explanation: 0.571 is greater than 0.4. Therefore, 4/7 is greater than 2/5 and the answer to the question "Is 4/7 greater than 2/5?" is yes. Note: When comparing fractions such as 4/7 and 2/5, you could also convert the fractions (if necessary) so they have the same denominator and then compare which numerator is larger.

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3 years ago
Which property of addition is shown below?
natta225 [31]
Inverse property is being shown
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2 years ago
Find the Measure of angle O<br> (see image)<br> Only real answers, please
-Dominant- [34]

Answer:

From the given figure we can see that :---

MN||PO, MN=PO and MP=NO

Therefore, angle M=angle N (adjacent sides of the trapezoid)

(8x - 16)  =  (6x + 20) \\ 2x = 36 \\  \boxed{x = 18}

angle M=angle N= (6×18)+20=108+20 =128°

angle O =(180°-128°)=52°

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3 0
3 years ago
Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.
Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

|AB|=\sqrt{(4--1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{5^2+(0)^2}

\Rightarrow |AB|=\sqrt{25}

\Rightarrow |AB|=5 units.

The length of side BC

|BC|=\sqrt{(3-4)^2+(-1-2)^2}

\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}

\Rightarrow |BC|=\sqrt{1+9}

\Rightarrow |BC|=\sqrt{10}

The length of side AC

|AC|=\sqrt{(3--1)^2+(-1-2)^2}

We simplify to obtain;

|AC|=\sqrt{(3+1)^2+(-3)^2}

\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}

|AC|=\sqrt{16+9}

|AC|=\sqrt{25}

|AC|=5\:units

Since |AC|=5\:units=|AB|, the given triangle is an isosceles triangle.

The correct answer is

6 0
3 years ago
Read 2 more answers
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