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katrin [286]
2 years ago
14

a basketball court is a rectangle with a perimeter of 1040 feet. The length is 200 feet more than the width. What is the width a

nd length of the basketball court?
Mathematics
2 answers:
PilotLPTM [1.2K]2 years ago
6 0
Length = width + 200

x + x + x + 200 + x + 200 = 1040 \\ 4x + 400 = 1040 \\ 4x = 640 \\ x = 160
Length = 160 + 200 = 360 feet

Answer :
Width = 160 feet,
Length = 360 feet

Hope this helps. - M
Ronch [10]2 years ago
3 0
If you do 1040-400 you get 640
then you need to divide that by 4 to get 160 leaving you with the width, to get the length you have to add 200 to the width meaning the length is 360

length = 360
width = 160
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Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
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Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

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2 years ago
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