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coldgirl [10]
3 years ago
7

3b-14/3b = 5b+2/3b b= ?

Mathematics
2 answers:
Temka [501]3 years ago
8 0

Answer:

A) -8

Step-by-step explanation:

You have to make the whole equation equal to zero. so rewrite the equation and equal it to zero. Write all numerators above the common denominator

3(b-5)+1-(5b+2) over 3b equal zero

Then remove parentheses

3b-15+1-5b-2 over 3b equals zero

Then collect the like terms

Calculate

-2b-16 over 3b equals zero

Then set the numerator equal to zero

-2b-16=0

Then move constant to the right

-2b=16

Then divide both sides by -2

b=-8

WINSTONCH [101]3 years ago
5 0

First of all, observe that all fractions exist as long as b is not zero.

Multiply both numerator and denominator of the first fraction by 3:

\dfrac{3b-15}{3b}+\dfrac{1}{3b}=\dfrac{5b+2}{3b}

Now all fractions have the same denominator. Under the assumption that b is not zero, multiply both sides by 3b:

3b-15+1=5b+2 \iff 3b-14=5b+2

Subtract 3b from both sides:

-14=2b+2

Subtract 2 from both sides:

-16=2b

Divide both sides by 2:

b=-8

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