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coldgirl [10]
3 years ago
7

3b-14/3b = 5b+2/3b b= ?

Mathematics
2 answers:
Temka [501]3 years ago
8 0

Answer:

A) -8

Step-by-step explanation:

You have to make the whole equation equal to zero. so rewrite the equation and equal it to zero. Write all numerators above the common denominator

3(b-5)+1-(5b+2) over 3b equal zero

Then remove parentheses

3b-15+1-5b-2 over 3b equals zero

Then collect the like terms

Calculate

-2b-16 over 3b equals zero

Then set the numerator equal to zero

-2b-16=0

Then move constant to the right

-2b=16

Then divide both sides by -2

b=-8

WINSTONCH [101]3 years ago
5 0

First of all, observe that all fractions exist as long as b is not zero.

Multiply both numerator and denominator of the first fraction by 3:

\dfrac{3b-15}{3b}+\dfrac{1}{3b}=\dfrac{5b+2}{3b}

Now all fractions have the same denominator. Under the assumption that b is not zero, multiply both sides by 3b:

3b-15+1=5b+2 \iff 3b-14=5b+2

Subtract 3b from both sides:

-14=2b+2

Subtract 2 from both sides:

-16=2b

Divide both sides by 2:

b=-8

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Bas_tet [7]
A.) Since there are no restrictions as to the dimensions of the candle except that their volumes must equal 1 cubic foot and that each must be a cylinder, we have the freedom to decide the candles' dimensions. 

I decided to have the candles equal in volume. So, 1 cubic foot divided by 8 gives us 0.125 cubic foot, 216 in cubic inches.

With each candle having a volume of 216 cubic inches, I assign a radius to each: 0.5 in, 1.0 in, 1.5 in, 2.0 in, 2.5 in, 3.0 in, 3.5 in, and 4.0 in. Then, using the formula of the volume of a cylinder, which is:

V=pi(r^2)(h)

we then solve the corresponding height per candle. Let us let the value of pi be 3.14.

Hence, we will have the following heights (expressed to the nearest hundredths) for each of the radius: for 

r=2.5 in: h=11.01 in
r=3.0 in: h= 7.64 in
r=3.5 in: h= 5.62 in
r=4.0 in: h= 4.30 in
r=4.5 in: h= 3.40 in
r=5.0 in: h= 2.75 in
r=5.5 in: h= 2.27 in
r=6.0 in: h= 1.91 in

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7 0
3 years ago
A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2
Yuliya22 [10]

A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.

Answer: The correct option is B) about 34%

Proof:

We have to find P(4.2

To find P(4.2, we need to use z score formula:

When x = 4.2, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{4.2-5.1}{0.9}=\frac{-0.9}{0.9}=-1

When x = 5.1, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{5.1-5.1}{0.9}=0

Therefore, we have to find P(-1

Using the standard normal table, we have:

P(-1= P(z

                               =0.50-0.1587

                               =0.3413 or 34.13%

                               = 34% approximately

Therefore, the percent of data between 4.2 and 5.1 is about 34%

7 0
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