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coldgirl [10]
3 years ago
7

3b-14/3b = 5b+2/3b b= ?

Mathematics
2 answers:
Temka [501]3 years ago
8 0

Answer:

A) -8

Step-by-step explanation:

You have to make the whole equation equal to zero. so rewrite the equation and equal it to zero. Write all numerators above the common denominator

3(b-5)+1-(5b+2) over 3b equal zero

Then remove parentheses

3b-15+1-5b-2 over 3b equals zero

Then collect the like terms

Calculate

-2b-16 over 3b equals zero

Then set the numerator equal to zero

-2b-16=0

Then move constant to the right

-2b=16

Then divide both sides by -2

b=-8

WINSTONCH [101]3 years ago
5 0

First of all, observe that all fractions exist as long as b is not zero.

Multiply both numerator and denominator of the first fraction by 3:

\dfrac{3b-15}{3b}+\dfrac{1}{3b}=\dfrac{5b+2}{3b}

Now all fractions have the same denominator. Under the assumption that b is not zero, multiply both sides by 3b:

3b-15+1=5b+2 \iff 3b-14=5b+2

Subtract 3b from both sides:

-14=2b+2

Subtract 2 from both sides:

-16=2b

Divide both sides by 2:

b=-8

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3 years ago
What is 4 over 8+ 2 over 8+ 2 over 4?
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A music teacher asked 23 students in the band how many hours they practiced playing their instrument each week. The results are
valkas [14]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

A music teacher asked 23 students in the band how many hours they practiced playing their instrument each week. The results are shown in the dot plot. Which statement best describes the data?

a. The data are skewed left, so most student's practice times are more than the mean practice time.

b. The data are skewed left, so most student's practice times are less than the mean practice time.

c. The data are skewed right, so most student's practice times are less than the mean practice time.

d. The data are skewed right, so most student's practice times are more than the mean practice time.

Answer:

The correct option is a.

The data are skewed left, so most student's practice times are more than the mean practice time.

Step-by-step explanation:

Refer to the attached box plot which shows number of hours the students spent on practice for playing their instrument each week.

When the data distribution is not symmetric around the mean then it is either skewed to right or skewed to left.

The given box plot is skewed to the left since the tail of the distribution on the left side is longer than the right side or in other words, most of the data is leaning to the right side of the curve.

Due to this, most student's practice times are more than the mean practice time.

A left skewed distribution is also known as negatively skewed distribution.

Therefore, we can conclude that the correct option is a.

a. The data are skewed left, so most student's practice times are more than the mean practice time.

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