Answer:
x=-1, y = 2, z = 1
Step-by-step explanation:
We are given with three equations and we are asked to find the solution to them.
2x + 2y + 3z = 5 ------------- (A)
6x + 3y + 6z = 6 --------------(B)
3x + 4y + 4z = 9 ---------------(C)
Step 1 .
multiplying equation (A) by 3 and subtracting B from the result
6x + 6y + 9z = 15
6x + 3y + 6z = 6
- - - = -
_______________
3y+3z=9
y+z=3
y=3-z ----------------- (C)
Step 2.
Substituting this value of y in equation B and C
6x + 3(3-z) + 6z = 6
6x+9-3z+6z=6
6x+3z=-3
2x+z=-1 ----------------(D)
3x + 4(3-z) + 4z = 9
3x+12-4z+4z=9
3x=-3
x=-1 ------------ (E)
Putting this value f x in (D)
2(-1)+z=-1
-2+z=-1
z=1
Now we put this value of z in equation (C)
y=3-z
y=3-1
y=2
Hence we have
x=-1, y=2 and z=1
9514 1404 393
Answer:
![\sqrt[3]{2197}, 14\frac{1}{3}, 13\frac{12}{8}, \sqrt{213.16}, 15, 2^4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2197%7D%2C%2014%5Cfrac%7B1%7D%7B3%7D%2C%2013%5Cfrac%7B12%7D%7B8%7D%2C%20%5Csqrt%7B213.16%7D%2C%2015%2C%202%5E4)
Step-by-step explanation:
The values of the given numbers, in order, rounded to 1 decimal place are ...
![\begin{array}{cc}\sqrt{213.16}&14.6\\14\frac{1}{3}&14.3\\15&15.0\\13\frac{12}{8}&14.5\\2^4&16.0\\\sqrt[3]{2197}&13.0\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7D%5Csqrt%7B213.16%7D%2614.6%5C%5C14%5Cfrac%7B1%7D%7B3%7D%2614.3%5C%5C15%2615.0%5C%5C13%5Cfrac%7B12%7D%7B8%7D%2614.5%5C%5C2%5E4%2616.0%5C%5C%5Csqrt%5B3%5D%7B2197%7D%2613.0%5Cend%7Barray%7D)
Their least-to-greatest ordering is shown above.
Please I think the question is not complete
Answer:
6) 24+4x
7) -24x+32
8) -21+42x
9)-24x-12
10) 72- 18x
Step-by-step explanation:
for each problem, you need to distribute the single variable to the parenthesis for the final answer. For example, 3 (4x-25) > 3 x 4x = 12x > 3x-25 = -75 now you put both answers together making it 12x-75
-4 times -2 equals 8.
8 times -1 equals -8.
Therefore, the point on your number line that is on -8 is your answer!
