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san4es73 [151]
3 years ago
12

Express 0.000000298 in scientific notation

Mathematics
1 answer:
Olenka [21]3 years ago
5 0
The expression would be 2.98 * 10 to the -7 power? Please tell me if I'm wrong.
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Rewrite this standard form quadratic equation into vertex form by completing the square. Upload your work here to show your thin
Alex787 [66]

Solution :

Given the equation :

$y = x^2 - 6x+3 $

$y=1(x^2 - 6x +n)+3$

$n = \left(\frac{b}{2}\right)^2$

$n = \left(\frac{6}{2}\right)^2$

n = 9

$y=1(x^2 - 6x +9-9)+3$

$y=1(x^2 - 6x +9)-9+3$

$y=1(x-3)^2- 6$

Therefore the vertex form of $y = x^2 - 6x+3 $  is  $y=1(x-3)^2- 6$.

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Step-by-step explanation:

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The smallest y can be is y = -1. The largest it can be is y = 1. The value of y can be anything in between. The value of y is a real number.

Answer: Choice D) All real numbers between -1 and 1 including -1 and 1

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Tatiana is practicing shooting. The coordinates (in m) of the barrel of her gun and the target are (5, 3, 1) and (38, 41, 3). Wh
saul85 [17]

Answer:

d=\sqrt{2,537}\ m   or  d=50.37\ m

Step-by-step explanation:

we know that

the formula to calculate the distance between two points in three dimensions is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}+(z2-z1)^{2}}

Let

A(5,3,1)  -----> coordinates of the barrel of her gun

B(38,41,3)  -----> coordinates of the target

substitute the values

d=\sqrt{(41-3)^{2}+(38-5)^{2}+(3-1)^{2}}

d=\sqrt{(38)^{2}+(33)^{2}+(2)^{2}}

d=\sqrt{1,444+1,089+4}

d=\sqrt{2,537}\ m

d=50.37\ m

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