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Andrews [41]
3 years ago
7

NEED HELP ASAP! Find the area of the shaded region. All angles are right angles.

Mathematics
1 answer:
zhenek [66]3 years ago
6 0

Answer:

166 m^2

Step-by-step explanation:

The enclosing rectangle is 9m by 29m, so is 261 m^2. From that, the white space of 5m by 19m = 95 m^2 must be subtracted. The result is that the shaded area is ...

261 m^2 -95 m^2 = 166 m^2

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You can figure out if two fractions are bigger by just cross multiplying the numerator and denominator of each fraction.  

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\frac{5}{12} \frac{3}{7}
5 * 7 = 35, 3 * 12 = 36
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Question 19 Unsaved
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A response variable you are trying to measure once you've done the experiment.

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Answer:

The slopes of line segments AC and AD are same or constant i.e \frac{1}{3}

Step-by-step explanation:

We need to find slopes of AC and AD and tell if they are same or not.

The formula used to calculate slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

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We have A=(3,2) and C=(0,1)

Finding slope using formula:

We have x_1=3, y_1=2, x_2=0,y_2=1

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{1-2}{0-3}\\Slope=\frac{-1}{-3}\\Slope=\frac{1}{3}

So, Slope of AC is \frac{1}{3}

Finding slope of AD

We have A=(3,2) and C=(9,4)

Finding slope using formula:

We have x_1=3, y_1=2, x_2=9,y_2=4

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{4-2}{9-3}\\Slope=\frac{2}{6}\\Slope=\frac{1}{3}

So, Slope of AD is \frac{1}{3}

So, the slopes of line segments AC and AD are same or constant i.e \frac{1}{3}

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