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3 years ago

13

Each week, you drive 150 miles. Your car gets 25 miles to the gallon, and gas prices are $3 per gallon. How much gas money will

you spend on gas each week?

2 answers:

aleksandr82 [10.1K]3 years ago

7 0

150 mi gal $3
x -------- x ------ = $18
25 mi gal

Gwar [14]3 years ago

4 0

YOU WILL SPEND 450 ON GAS EACH WEEK

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Can someone help me ? Its due today please

anastassius [24]

Answer:

x=3

y=5

Step-by-step explanation:

3x+2y=19

- 2x+2y=16

_____________

x=3

3(3)=9

19-9=10

10÷2=5

y=5

6 0

3 years ago

Read 2 more answers

What value of x would satisfy the equation 6x-4(2x+1)= 10 as a improper fraction

Serga [27]

X= -7
Hope it helps......

5 0

3 years ago

How do you simplify this?<br>x²y+xy² / y²+2/5 × xy

polet [3.4K]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

How do you simplify this?
x²y+xy² / y²+2/5 × xy

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\sf\frac{ { x }^{ 2 } y+x { y }^{ 2 } }{ { y }^{ 2 } + \frac{ 2 }{ 5 } \times xy } \\$

Factor the expressions that are not already factored.

_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> $\downarrow$

$\sf \: x ^ { 2 } y + x y ^ { 2 }$

Factor out xy.

$\sf \: xy\left(x+y\right)$

<u>DENOMINATOR</u> $\downarrow$

$\sf{ y }^{ 2 } + \frac{ 2 }{ 5 } \times xy \\$

Factor out 1/5.

$\sf \: {\frac{1}{5}y\left(2x+5y\right)} \\$

_____

Continuing...

$\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)} \\$

Cancel out y in both the numerator and denominator.

$\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)} \\$

Expand the expression.

$\sf\frac{x^{2}+xy}{\frac{2}{5}x+y} \\$

This can further simplified to as $\downarrow$

$= \boxed{\boxed{\bf\frac{5x\left(x +y\right)}{2x+5y}}}$

3 0

3 years ago

30. What is the solution to the system of equations? (1 point)

sesenic [268]

Answer:

Option B) (-1,7,5) is correct.

The solution to the given system of equation is (-1,7,5)

Step-by-step explanation:

Given system of equations are

$-7x-2y+z=-2\hfill (1)$

$6x-y-z=-18\hfill (2)$

$5x+4y-z=18\hfill (3)$

To find the solution of the given system of equations by using Elimination method:

Now adding equations (1) and (2)

$-7x-2y+z=-2$

$6x-y-z=-18$

_________________

$-x-3y=-20$

________________

$-x-3y=-20$

$-(x+3y)=-20$

$x+3y=20\hfill (4)$ (since "-" getting cancelled)

Now adding equations (1) and (3)

$-7x-2y+z=-2$

$5x+4y-z=18$

_________________

$-2x+2y=16$

________________

$-2x+2y=16$

$2(-x+y)=16$

$-x+y=8\hfill (5)$

Now adding equations (4) and (5)

$x+3y=20$

$-x+y=8$

_________________

$4y=28$

________________

$y=\frac{28}{4}$

Therefore y=7

Substituting y=7 in equation (4)

$x+3y=20$

$x+3(7)=20$

$x+21=20$

$x=20-21$

Therefore x=-1

Now substituting the values x=-1 and y=7 in equation (1) we get

$-7x-2y+z=-2$

$-7(-1)-2(7)+z=-2$

$7-14+z=-2$

$z=-2+7$

Therefore z=5

Therefore the solution to the given system of equation is (-1,7,5)

Therefore Option B) (-1,7,5) is correct.

8 0

3 years ago

What is the value of the expression 3/19 divided 7/2

Andrew [12]

Answer:

Exact Form:

6/133

Decimal Form:

0.04511278

Step-by-step explanation:

3 0

3 years ago