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4 years ago

PLEASE HELP 22 POINTS!!!!!!!!!!!

Mathematics

1 answer:

Elanso [62]4 years ago

6 0

Answer : D) {4R, 4B, 4C, 5R, 5B, 5C, 6R, 6B, 6C}

Step-to step explanation:

Given : Choices for phone models= 4, 5, and 6 ( 3 choices)

Choices for protective case = red (R), blue (B), or camo (C) ( 3 choices)

Number of different refurbished phone can be made = ( Choices for phone models) x (Choices for protective case)

= 3 x 3 = 9 choices

Therefore , the number of different choices he has = 9

Since only option D has all 9 choices (each phone models pair with each kin of protective case)

Hence, all the different choices he has = {4R, 4B, 4C, 5R, 5B, 5C, 6R, 6B, 6C}

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Which represents the solution set to the inequality 5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4)?

Nina [5.8K]

1. Simplify the inequality $5.1(3 + 2.2x) > -14.25 - 6(1.7x + 4):$

$15.3+11.22x>-14.25-10.2x-24,\\
15.3+11.22x>-10.2x-38.75.$

2. Separate terms with x and without x in different sides:

$11.22x+10.2x>-38.75-15.3.$

3. Add similar terms:

$21.42x>-54.05.$

4. Divide by 21.42:

$x>-\dfrac{54.05}{21.42} ,\\ \\x>-2.5.$

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3 years ago

Read 2 more answers

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nirvana33 [79]

Kind of true and kind of false : Sometimes they are, but there is nothing that force two acture triangles to be similar, even if they have the same measurement of the acute angle.

For that you would need to have 3 angles the same.

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3 years ago

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Is x+y=6 a direct variation? Why or why not?

ivanzaharov [21]

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3 years ago

I don’t understand HELP ME PLEASEEEEEE!<br> !

Bezzdna [24]

Answer:

p(greater than or equal to) -15

Step-by-step explanation:

6 0

2 years ago

During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th

ser-zykov [4K]

Answer: 0.5898

Step-by-step explanation:

Given : J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901 (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

$P(X=x)^nC_xp^x(1-p)^{n-x}$

, where n= total trials

p= probability of getting in each trial.

Let x be binomial variable that represents the number of a=makes.

n= 14

p= 0.901 (from (1))

The probability that he makes at least 13 of them will be :-

$P(x\geq13)=P(x=13)+P(x=14)$

$=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898$

∴ The required probability = 0.5898

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3 years ago