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marshall27 [118]
3 years ago
11

If it takes 16.73 mL of a 0.253 M LiOH solution to neutralize10.00 mL of HBr, what is its concentration?

Biology
1 answer:
krek1111 [17]3 years ago
5 0
The neutralization reaction is written as:

LiOH + HBr = LiBr + H2O

0.253 mol LiOH / L solution ( .01673 L solution ) ( 1 mol HBr / 1 mol LiOH ) = 4.233 x 10^-3 mol HBr

Concentration of HBr solution = <span>4.233 x 10^-3 mol HBr / .01 L solution = 0.423 M HBr solution</span>
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