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3 years ago

6

What is the y-intercept of the equation 4×+2y=12?

2 answers:

DerKrebs [107]3 years ago

8 0

Change the equation to y-intercept form
4x+2y=12
2y= -4x + 12
y = -2x + 6
The y-intercept is 6, since the constant in the y-intercept form function is 6.

Reil [10]3 years ago

5 0

The Y-intercept is a point where the line crosses the Y lines. That means it would be the point where X=0. Then to find the Y-intercept you only need to insert X=0 into the equation. The calculation would be:

<span> 4×+2y=12
4(0) + 2 Y= 12
2Y =12
Y=6</span>

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Mashcka [7]

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Step-by-step explanation:

Integration Rule:

$\int x^n dx= \frac{x^{n+1}}{n+1}+c$
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Given differential equation is

$x^2 \frac{dw}{dx}= \sqrt{w}(2x+5)$

$\Rightarrow x^2 dw= \sqrt{w} (2x+5) dx$ [ multiplying dx both sides]

$\Rightarrow \frac{dw}{\sqrt w}= \frac{(2x+5)}{x^2} dx$ [ dividing $x^2\sqrt w$ both sides]

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$\int \frac{dw}{\sqrt w}=\int \frac{(2x+5)}{x^2} dx$

$\Rightarrow \int w^{-\frac12} dw=\int (\frac{2x}{x^2}+\frac{5}{x^2} )dx$

$\Rightarrow \int w^{-\frac12} dw=\int \frac{2}{x}dx +\int\frac{5}{x^2} dx$

$\Rightarrow \frac{w^{-\frac12+1}}{-\frac12+1} =2ln x+5 \frac{x^{-2+1}}{-2+1}+c$ [ c is arbitrary constant]

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Therefore the general solution is

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