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Andrej [43]
3 years ago
9

URGENT DUE BY 2:30 WILL RATE GOOD:)

Mathematics
2 answers:
Dmitry [639]3 years ago
7 0
Areashaded=areabigcircle-areasmallcircle


areacircle=pir^2
d/2=r

big diameter=20.4, so radius i 20.4/2=10.2cm

small is 10.8/2=5.4


so
big-small
pi10.2^2-pi5.4^2
pi(104.04-29.16)
pi(74.88)
using 3.14=pi
235.1232 cm^2


answer is B

Mamont248 [21]3 years ago
7 0

Answer: the answer is B. 235.1

Step-by-step explanation:

For the large circle the

Area = pi. • r • r

In other words,

Area = 3.14 • 10.2 • 10.2

Which equals 326.7

Then for the small circle the

Area = 3.14 • 5.4 • 5.4

Which equals 91.6

Then to find the shaded area,

326.7 - 91.6 =

235.1 cm squared

Hope this helps! :)

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(x, y) = ( cos 45, sin 45) =

=\text{ (}\frac{\sqrt[]{2}}{2}\text{ , }\frac{\sqrt[]{2}}{2}\text{ )}

The correct option is A

4 0
1 year ago
Which property of multiplication is shown?<br><br> 9 × 0 − 6 × 0 = (9 − 6) × 0
JulsSmile [24]

Answer: Associative property

Step-by-step explanation: it is the same equation but they switched the numbers around on the other side of the equal sign so therefore its associative property

7 0
3 years ago
Read 2 more answers
In an article regarding interracial dating and marriage recently appeared in a newspaper. Of 1719 randomly selected adults, 311
Bingel [31]

Answer:

Step-by-step explanation:

Hello!

The parameter of interest in this exercise is the population proportion of Asians that would welcome a person of other races in their family. Using the race of the welcomed one as categorizer we can define 3 variables:

X₁: Number of Asians that would welcome a white person into their families.

X₂: Number of Asians that would welcome a Latino person into their families.

X₃: Number of Asians that would welcome a black person into their families.

Now since we are working with the population that identifies as "Asians" the sample size will be: n= 251

Since the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the variable distribution to normal.

Z_{1-\alpha /2}= Z_{0.975}= 1.965

1. 95% CI for Asians that would welcome a white person.

If 79% would welcome a white person, then the expected value is:

E(X)= n*p= 251*0.79= 198.29

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.79*0.21=41.6409

√V(X)= 6.45

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

198.29±1.965*6.45

[185.62;210.96]

With a 95% confidence level, you'd expect that the interval [185.62; 210.96] contains the number of Asian people that would welcome a White person in their family.

2. 95% CI for Asians that would welcome a Latino person.

If 71% would welcome a Latino person, then the expected value is:

E(X)= n*p= 251*0.71= 178.21

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.71*0.29= 51.6809

√V(X)= 7.19

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

178.21±1.965*7.19

[164.08; 192.34]

With a 95% confidence level, you'd expect that the interval [164.08; 192.34] contains the number of Asian people that would welcome a Latino person in their family.

3. 95% CI for Asians that would welcome a Black person.

If 66% would welcome a Black person, then the expected value is:

E(X)= n*p= 251*0.66= 165.66

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.66*0.34= 56.3244

√V(X)= 7.50

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

165.66±1.965*7.50

[150.92; 180.40]

With a 95% confidence level, you'd expect that the interval [150.92; 180.40] contains the number of Asian people that would welcome a Black person in their family.

I hope it helps!

5 0
3 years ago
“Lines that appear to be tangent are tangent. O is the center of the circle. What is the value of x?”
ahrayia [7]
Hello,

Let's calculate ∠O:
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x=90-68=22°

3 0
3 years ago
PLEASE HELP BRAINIEST WILL BE AWARD
ludmilkaskok [199]

Answer:

Your answer would be C. Hold on lemme check.... Yes its C.

Step-by-step explanation:

Hope I helped LOL

5 0
3 years ago
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