Solving a system of linear equations using the substitution method.
5x+4y=-26
5-x=-6y
2 answers:
Solve for x in 2nd equation times -1 both sides x-5=6y add 5 x=6y+5 sub 5(6y+5)+4y=-26 30y+25+4y=-26 34y+25=-26 minus 25 both sides 34y=-51 divide both sides by 34 y=-3/2 sub back x=6y+5 x=6(-3/2)+5 x=-18/2+5 x=-9+5 x=-4 (-4,-3/2) is solution
We write x in terms of y in order to substitute using the second equation -x=-6y-5 x= 6y+5 We substitute what we got above in the first equation 5(6y+5)+4y=-26 We solve for y 30y+25+4y=-26 34y+25=-26 34y=-51 y=-51/34 Then we plug what we got for y back in our first equation in order to get the value of x as well x=6(-51/34)+5 x=-4 So the solutions are: x=-4 y=-1.5
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vertices :
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