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Vesna [10]
3 years ago
5

The square of a number exceeds the number by 72. Find the number

Mathematics
1 answer:
balu736 [363]3 years ago
8 0
X^2 = x + 72 you have a quadratic.
x^2 - x - 72 = 0
(x - 9)*(x + 8) = 0
x = 9 or x = - 8

We have to check this one. One of the answers could be wrong.
9^2 = 9 + 72
81 = 81 This one checks out and is OK.

(-8)^2 = -8 + 72
64 = - 8 + 72 
64 = 64.
Both answers work.
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The sum of three consecutive odd intergers is 17 less that four the smallest interger?​
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Answer:

The integers are 23, 25, 27

Step-by-step explanation:

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3 0
4 years ago
A collection of quarters and dimes is worth $12.40. There are 67 coins in all.
padilas [110]
Let:
x= quarters
y= dimes


x+y=67
and
.25x+.10y=12.40

x=67-y

.25(67-y)+.10y=12.40
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16.75-.15y=12.40
Lets rearrange this:
-.15y+16.75=12.40
        -16.75    -16.75
-.15y=-4.35
the negatives cancel out
.<u>15y</u>=<u>4.35
</u>.15<em /><em>     <u /></em>.15
y=29

Back to the original x=67-y
x=67-29
x=38

So,
x=38
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<em />
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