A piece of aluminum occupies a volume of 13.0 milliliters and weighs 52.9 grams. What is its density of the aluminum rounded to
1 answer:
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Answer:
m∠S = 29.5
Explanation:
Q
S R
In this triangle, QR = SQ, which means its an isosceles triangle, angle S and R is similar.
<u>Thus solve:</u>
m∠S = (180° - 121°)/2
m∠S = 29.5°