Question

What is the equation of the line that is parallel to the given line and passes through the point (–2, 2)?

Answer 1

The given blue line passes through points (0, -3) and (-5, -4). This means that its slope m is 

$\displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}=\frac{-3-(-4)}{0-(-5)}= \frac{-3+4}{5}= \frac{1}{5}$.

Any line parallel to this line has the same slope, that is 1/5.


The equation of the line with slope 1/5, passing through the point (-2, 2) is:

             $y-2= \frac{1}{5}(x-(-2))\\\\y-2= \frac{1}{5}x+ \frac{2}{5}$. 


Adding 2 to both sides, we have: 
 
                    $y= \frac{1}{5}x +\frac{12}{5}$.


Answer: $y= \frac{1}{5}x +\frac{12}{5}$.

Answer 2

Answer:

b

Step-by-step explanation:

The given blue line passes through points (0, -3) and (-5, -4). This means that its slope m is 

.

Any line parallel to this line has the same slope, that is 1/5.