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Mamont248 [21]
4 years ago
9

PLEASE HELP! 85 POINTS This needs submitted in a hour or less! Thank You in advance!

Mathematics
1 answer:
vlabodo [156]4 years ago
5 0

Answer:

It is 20x plus 2

Step-by-step explanation:

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The value of m, if 3,18,m,42 are in proportion
Tom [10]

If its a proportion then

\\ \sf\longmapsto 42-m=m-18

\\ \sf\longmapsto 42+18=m+m

\\ \sf\longmapsto 2m=60

\\ \sf\longmapsto m=\dfrac{60}{2}

\\ \sf\longmapsto m=30

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%283a%5E2b%29%5E3%7D%7B9%28ab%29%5E4%7D" id="TexFormula1" title="\frac{(3a^2b)^3}{9(
VladimirAG [237]

You first multiply the outside exponents into the numbers in the parentheses.

When you have an exponent being multiplied directly to another exponent, you multiply the exponents together.

For example(because I am a bad explainer):

(x^{2} )^4= x^{2(4)} = x^8

(x^4)^3 = x^{4(3)} = x^{12}


When you divide an exponent by an exponent, you subtract the exponents

For example:

\frac{x^4}{x^1} =x^{4-1}=x^3


When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive

For example:

x^{-3}=\frac{1}{x^3}

\frac{1}{y^{-5}}=\frac{y^5}{1}=y^5



\frac{(3a^2b)^3}{9(ab)^4}

You can think of it like this if you want:

\frac{(3^1a^2b^1)^3}{9(a^1b^1)^4}  Now multiply the outside exponents into the exponents in the parentheses

\frac{3^3a^6b^3}{9(a^4b^4)} =\frac{27a^6b^3}{9(a^4b^4)} Divide 27 and 9

\frac{3a^6b^3}{a^4b^4} =(3)(a^{6-4})(b^{3-4})=(3)(a^2)(b^{-1})=(3)(a^2)(\frac{1}{b^1})=\frac{3a^2}{b}



Your answer is \frac{3a^2}{b}



5 0
3 years ago
Convert 7 over 8 to a decimal.<br><br> 0.375<br> 0.875<br> 0.925<br> 0.965
zubka84 [21]
7/8 in decimal form is 0.875 because you are dividing 7 by 8
3 0
3 years ago
Read 2 more answers
2x + 6 = x +15 solve for x please and thank you
slava [35]

Answer:

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Simultaneous equations 2x+3y=13 4x-y=-2
Rufina [12.5K]

Answer:

(0.5, 4 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = 13 → (1)

4x - y = - 2 → (2)

Multiplying (2) by 3 and adding to (1) will eliminate the term in y

12x - 3y = - 6 → (3)

Add (1) and (3) term by term to eliminate y

14x = 7 ( divide both sides by 14 )

x = 0.5

Substitute x = 0.5 into either of the 2 equations and evaluate for y

Substituting into (1)

2(0.5) + 3y = 13

1 + 3y = 13 ( subtract 1 from both sides )

3y = 12 ( divide both sides by 3 )

y = 4

Solution is (0.5, 4 )

3 0
4 years ago
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