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4 years ago

Can someone explain? Brainliest + Points! :D

Mathematics

1 answer:

Ulleksa [173]4 years ago

8 0

I'm not I understand. The range is the highest value minus the lowest value, which on the graph is 10-4=6.

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PLZ HELP THIS IS HARD I WILL FIVE BRAINLIEST

bagirrra123 [75]

Answer:

$2\frac{1}{3}\: ft$

Step-By-Step Explanation:

$Height\: of \:sail = 1\frac{1}{6}\: ft = \frac{7}{6}\: ft\\Base\: of \:sail = 4\: ft \\Area\: of \:sail =\frac{1}{2} \times base \times height\\=\frac{1}{2} \times \frac{7}{6} \times 4\\= \frac{7}{6} \times 2\\=\frac{7}{3}\\=2\frac{1}{3}\: ft$

6 0

3 years ago

The Smith family bought carpet for their basement. It originally cost $1,600. The company offered and installment plan for 12 mo

Taya2010 [7]

Answer:

$1,800

Step-by-step explanation:

If the Smiths agree to the installment plan and pay $150 every month for 12 months, it will add up to $1,800 at the end of the year.

8 0

2 years ago

A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 y

Anestetic [448]

Answer:

$\frac{1}{4180}$

Step-by-step explanation:

GIVEN: A snack-size bag of M&Ms candies is opened. Inside, there are $12$ red candies, $12$ blue, $7$ green, $13$ brown, $3$ orange, and $10$ yellow. Three candies are pulled from the bag in succession, without replacement.

TO FIND: What is the probability that the first two candies drawn are orange and the third is green.

SOLUTION:

Total candies in the bag $=57$

Probability that first ball is orange, $P(A)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}$

$=\frac{3}{57}=\frac{1}{19}$

Probability that second ball is orange, $P(B)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}$

$=\frac{2}{56}=\frac{1}{28}$

Probability that third ball is green, $P(C)=\frac{\text{total green candies in bag}}{\text{total candies in bag}}$

$=\frac{7}{55}$

Now, probability that first two balls are orange and third is green is

$=P(A)\times P(B)\times P(C)$

$=\frac{1}{19}\times\frac{1}{28}\times\frac{7}{55}$

$=\frac{1}{19}\times\frac{1}{4}\times\frac{1}{55}$

$=\frac{1}{4180}$

Hence, probability that first two balls are orange and third is green is $\frac{1}{4180}$

3 0

3 years ago

A kite is flying at an angle of elevation of about 40 degrees. all 80 m of string have been let out. ignoring the sag in the str

VLD [36.1K]

Sin 40° = h / 80 m
0.6427876 = h / 80 m
h = 0.6427876 · 80 m
h = 51.423 m ≈ 50 m ( to the nearest 10 m )
Answer:
The height of the kite is about 50 m.

4 0

3 years ago

Solve for x: 2eˣ - 7 = 21

zepelin [54]

2eˣ - 7 = 21

2eˣ = 28

eˣ = 14 How do we isolate for x now? Well we know that aˣ=b can be converted to $x=log_{a}(b)$ .

x = $log_{e}(14)$ A shorthand for "log base e" is the natural log (ln).

x = ln(14)

x = 2.64 approx.

Exact answer: ln(14)

Approximation: 2.64

3 0

3 years ago